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andreyandreev [35.5K]
3 years ago
9

How do I do problem twelve you don’t have to give the answer because you can’t see the numbers but explain how I would do It

Mathematics
1 answer:
liraira [26]3 years ago
8 0

In order to do this you would multiply how much she used for 1/16 of the garden by 16. So 1/2 • 16 which is 8. So the answer is 8.

Hope this helps!

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A landscaper needs 3 4/8 pounds of plant food. He has 1 1/4 pounds in his truck, and another 4/6 pound at his shop. How many mor
kow [346]

Answer:

\frac{19}{12}\ pounds

or

1\frac{7}{12}\ pounds

Step-by-step explanation:

Let

x ----> the additional pounds of plant food needed for the landscaper

we know that

The additional pounds of plant food needed for the landscaper plus the pounds in his truck plus the pounds in his shop must be equal to the total pounds of plant food needed

so

The linear equation that represent this problem is

x+1\frac{1}{4}+\frac{4}{6}=3\frac{4}{8}

Convert mixed number to an improper fractions

1\frac{1}{4}=1+\frac{1}{4}=\frac{4*1+1}{4}=\frac{5}{4}

3\frac{4}{8}=3+\frac{4}{8}=\frac{3*8+4}{8}=\frac{28}{8}=\frac{14}{4}

Substitute in the expression above

x+\frac{5}{4}+\frac{4}{6}=\frac{14}{4}

solve for x

Multiply by (4*6) both sides to remove the fractions

24x+30+16=84

Combine like terms left side

24x+46=84

subtract 46 both sides

24x=84-46

24x=38

Divide by 24 both sides

x=\frac{38}{24}\ pounds

simplify

x=\frac{19}{12}\ pounds

Convert to mixed number

\frac{19}{12}\ pounds=\frac{12}{12}+\frac{7}{12}=1\frac{7}{12}\ pounds

3 0
3 years ago
Can someone plsss help?
natima [27]

Answer:

A

Step-by-step explanation:

I know math and (-10)/3 = -3.3 which is what the expression equals.

3 0
3 years ago
Read 2 more answers
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Answer:

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A line passes through the point (6,1) and has a slope of -3.
aleksklad [387]

\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{1})~\hspace{10em} \stackrel{slope}{m}\implies -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{-3}(x-\stackrel{x_1}{6})

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