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s2008m [1.1K]
4 years ago
12

Solve this inequality. 8x + 6 less than or equel to 54

Mathematics
1 answer:
Step2247 [10]4 years ago
6 0

Answer:

x\le 6

Step-by-step explanation:

We need to solve the given inequality 8x+6\le 54 ....(1)

Subtract 6 on both sides of the equation as :

8x+6-6\le 54-6\\\\8x\le 48

Dividing both sides of the equation by 8 such that,

x\le 6

So, the value of x is less than equal to 6. Hence, this is the required solution.

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the commutative property of addition lets you reorder terms. how is this property used to rewrite the expression
Galina-37 [17]

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Changing the order of addends does not change the sum.

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3 0
3 years ago
The curves r1(t) = 4t, t2, t3 and r2(t) = sin(t), sin(5t), 2t intersect at the origin. find their angle of intersection, θ, corr
san4es73 [151]
First get the tangent vectors by differentiating r1 and r2 
r_1 '(t) = (4,2t,3t^2) \\  \\  r_2'(t) = (cos (t), 5 cos(5t), 2)
Evaluate at t=0
r_1' = (4,0,0) \\  \\ r_2' = (1,5,2)

Use identity for angle between 2 vectors:
u*v = |u| |v| cos \theta

Evaluate dot product and unit vectors:
u*v = (4,0,0)*(1,5,2) = 4 \\  \\ |u| = \sqrt{4^2 +0^2+0^2} = 4 \\  \\ |v| = \sqrt{1^2 + 5^2+2^2} = \sqrt{30}

Sub into identity and solve for theta:
4 = 4 \sqrt{30} cos \theta \\  \\ cos\theta = \frac{1}{\sqrt{30}} \\  \\ \theta = 79.48

Answer:
Angle of intersection is about 79 degrees.




5 0
4 years ago
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