
-
9² = 12² + 15² - 2 (12) (15) cos (B)
81 = 144 + 225 - 360 cos(B)
81 = 369 - 360 cos (B)
360 cos (B) = 369 - 81
360 cos (B) = 288
cos (B) = 0.8
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Answer: Cosine B = 0.8
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12² = 15² + 9² - 2 (15)(9) cos (A)
144 = 225 + 81 - 270 Cos A
144 = 306 - 270 Cos A
270 Cos A = 162
Cos A = 3/5 or 0.6
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Answer: Cosine Angle A = 3/5
Answer:
Third turn point = 21 points
Step-by-step explanation:
Given:
First turn point = 12
Second turn point = 15
Find;
Third turn point
Computation:
First turn point = 12
Assume;
Point for outer circle = a
Point for inner circle = b
So,
3a = 12
Point for outer circle = 4 point
Second turn point = 15
So,
2a + b = 15
2(4) + b = 15
Point for inner circle = 7
Third turn point = 3 x 7
Third turn point = 21 points
Answer:

Step-by-step explanation:
∠E = 1/2 (mCD - mAB)
<u>Where mCD = 110° and mAB = 30°</u>
∠E = 1/2 (110° - 30°)
∠E = 1/2 (80°)
∠E = 40°
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
The Chef will prepare 320 soups for a large banquet
Step-by-step explanation:
chef thinks that 2 out of every 5 dinner guests will order soup
===> Order soup / total number of attender
= 2/5
Total guest = 800 ==> 4 people ordered soup is
2 /5 = x /800
cross multiplying
x = 2 x 800 / 5
= 320
The Chef will prepare 320 soups for a large banquet