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aev [14]
2 years ago
11

Find the zeroes of the following equation:

Mathematics
1 answer:
weqwewe [10]2 years ago
7 0

Answer:  \bold{x=\dfrac{1\pm \sqrt5}{2}}

                both zeros are irrational numbers

<u>Step-by-step explanation:</u>

Note: The question would have made more sense if if it was 2/x = x - 1 but I will answer it as written.

\dfrac{1}{x}=x-1\qquad \text{Restriction: }x\neq 0\\\\\\\text{Cross multiply, simplify, and set equal to zero:}\\1=x(x-1)\\\\1=x^2-x\\\\0=x^2-x-1\\\\\\\text{This is not factorable so you will need to use Quadratic Formula:}\\\\x=\dfrac{-(-1)\pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}\\\\\\x=\dfrac{1\pm \sqrt5}{2}

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A) (3)² = 3 × 3 and 10(8)² = 10 × 8 × 8

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For any number x, the square of the number denoted by (x)² is equal to 2 times x multiplied by itself or x*x.

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