The following ratios form a proportion. 5\18 = 10/90 True False

liq [111]

Show more of the cylinder

8 0

3 years ago

Nanu borrowed a certain sum at the rate of 10 % p.a. If she paid compound interest Rs. 1,290 at the end of two years compounded

Leokris [45]

Answer:

whats your answer please give

5 0

3 years ago

I have a very large equation to factor and need a quick way to factor it?

ludmilkaskok [199]

Can i have a real question please!

3 0

3 years ago

The radius of the large sphere is double the radius of the small sphere. How many times does the volume of the large sphere than

pshichka [43]

Answer:

8 times larger.

Step-by-step explanation:

The radius of the large sphere is double the radius of the small sphere.

Question asked:

How many times does the volume of the large sphere than the small sphere

Solution:

Let radius of the small sphere =  $x$ 

As the radius of the large sphere is double the radius of the small sphere:

Then, radius of the large sphere = $2x$

To find that how many times is the volume of the large sphere than the small sphere, we will divide the volume of large sphere by volume of small sphere:-

For smaller sphere: $Radius = x$

$Volume \ of \ sphere = \frac{4}{3} \pi r^{3}$

$=\frac{4}{3} \pi x^{3}$

For larger sphere: $Radius = 2x$

$Volume \ of \ sphere = \frac{4}{3} \pi r^{3}$

$=\frac{4}{3} \pi (2x)^{3}$

Now, we will divide volume of the larger by the smaller one:

$=\frac{4}{3} \pi (2x)^{3}\div\frac{4}{3} \times\frac{\pi }{1 } \times x^{3}\\ \\ =\frac{4}{3} \pi\times8x^{3} \times\frac{3}{4\pi }\ \times\frac{1}{x^{3} }$

$\frac{4}{3}\pi\ is \ canceled\ by\ \frac{3}{4\pi } \ and\ also\ x^{3} is\ canceled\ by \ \frac{1}{x^{3} }$

Now, we have

= $\frac{8}{1}$

Therefore, the volume of the large sphere is 8 times larger than the smaller sphere.

7 0

4 years ago

Read 2 more answers

A door 2m*1m is fixed on a wall.The wall is 8.5 long and 2m high.Find the cost of whitewashing the wall ₹40 per square meter.

Savatey [412]

Answer:

$600\ rupees$

Step-by-step explanation:

$We\ are\ given:\\Dimensions\ of\ the\ door=2m *1m\\Dimensions\ of\ the\ wall=8.5m*2m\\Cost\ of\ whitewashing\ of\ 1m^2=40\ rupees\\Hence,\\First\ lets\ consider\ the\ wall:\\Area\ of\ a\ rectangle= Length*Width\\Here,\\Length\ of\ the\ wall=8.5\ m\\Width\ of\ the\ wall=2\ m[As\ here\ width\ and\ height\ are\ the\ same\ thing]\\Hence,\\Area\ of\ the\ wall=8.5*2=17\ m^2$

$Now,\\Lets\ consider\ the\ door:\\As\ we\ know\ that,\\Area\ of\ a\ rectangle=Length*Width\\Here,\\Length\ of\ the\ door=2m\\Width\ of\ the\ door=1\ m\\Hence,\\Area\ of\ the\ door=2*1=2m^2\\\\Now,\\The\ area\ to\ be\ whitewashed=Area\ of\ the\ wall-Area\of\ the\ door\\Hence,\\The\ area\ to\ be\ whitewashed=17-2=15\ m^2\\\\As\ we\ know\ that,\\Cost\ of\ whitewashing\ 1\ m^2\ of\ the\ wall= 40\ rupees\\Hence,\\$

$Cost\ of\ whitewashing\ the\ whole\ wall=Area\ of\ the\ wall\ to\ be\\ whitewashed*Rate\ of\ whitewashing\ per\ m^2\\Hence,\\Cost\ of\ whitewashing\ the\ whole\ wall=15*40=600\ rupees$

8 0

3 years ago