The values for x and y are respectively given as
This is further explained below.
<h3>What is the values for
x and y ?</h3>
Generally, the equation for secent is mathematically given as

Therefore

80 = 130-x
x = 50
b) To Solve for y Now we find a measure of arc CD
ArcCD = 360-130-50
ArcCD = 180
In conclusion,(1/2) of the arc measure is equal to the angle that is on and inside a circle.
y = 180/2
y= 90
Read more about circle
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4=4 6=5 7=9 8=4 9=2 10=8 11=3 12=9
Answer:
170
Step-by-step explanation:
The given relations can be used to write and solve an equation for the number of stickers Peter has.
<h3>Setup</h3>
Let p represent the number of stickers Peter has. That is twice as many as Joe, so Joe has (p/2) stickers. Joe has 40 more stickers than Emily, so the number of stickers Emily has is (p/2 -40).
The total number of stickers is 300:
p +p/2 +(p/2 -40) = 300
<h3>Solution</h3>
2p = 340 . . . . . . . . . . . . . . add 40, collect terms
p = 170 . . . . . . . . . . . divide by 2
Peter has 170 stickers.
__
<em>Additional comment</em>
Joe has 170/2 = 85 stickers. Emily has 85-40 = 45 stickers.
We could write three equations in three unknowns. Solving those using substitution would result in substantially the same equation that we have above. Or, such a system of equations could be solved using a calculator's matrix functions, as in the attachment.
p +j +e = 300
p -2j +0e = 0
0p +j -e = 40
The least common denominator is C!
Hope this helps you! :)
Answer:
Hypothenus = 22
Step-by-step explanation:
From the question given above, we were told that the triangles are congruent (i.e same size). Thus,
AC = EF
BC = DE
To obtain the length of each Hypothenus, we shall determine the value of y and x. This can be obtained as follow:
For y:
AC = y + 3
EF = 2y + 1
AC = EF
y + 3 = 2y + 1
Collect like terms
3 – 1 = 2y – y
2 = y
y = 2
For x:
BC = 5x + 7
DE = 6x + 2y
y = 2
DE = 6x + 2(2)
DE = 6x + 4
BC = DE
5x + 7 = 6x + 4
Collect like terms
7 – 4 = 6x – 5x
3 = x
x = 3
Finally, we shall determine the length of each Hypothenus. This can be obtained as follow:
Hypothenus = BC
Hypothenus = 5x + 7
x = 3
Hypothenus = 5x + 7
Hypothenus = 5(3) + 7
Hypothenus = 15 + 7
Hypothenus = 22
OR
Hypothenus = DE
DE = 6x + 2y
y = 2
x = 3
Hypothenus = 6(3) + 2(2)
Hypothenus = 18 + 4
Hypothenus = 22