<em>Algebraic expressions</em> include both <u>alphabet </u>and <u>number</u> so that the value of the <u>alphabet</u> is to be <em>determined</em>. Thus the steps taken by Tyler are correct if x = 22.
ii. Tyler made no mistake.
<em>Algebraic expressions</em> include both <u>alphabet</u> and <u>number</u> so that the <em>value</em> of the <u>alphabet</u> is to be determined. The <u>value</u> of the <u>alphabet</u> in the <em>expression</em> would be determined by applying <em>mathematical operations</em> appropriately.
To solve the <u>question</u> given to Tyler, we have:
= -5
<u>square</u> both <em>sides</em> of the equation to have;
(x + 3) = 
x + 3 = 25
collect <em>like terms</em> to get;
x = 25 - 3
= 22
x = 22
1. Thus the equation is true if x = 22.
2. <u>Tyler</u> did not make any <u>mistake</u> in solving for x.
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#SPJ 1
They weigh the same --- One pound.
One pound of feathers = One pound of iron
Answer:
Option E 
Step-by-step explanation:
we have
we know that
For x> 5 both sides of the equation will be positive
Squared both sides
Subtract 4 both sides
Rewrite
Given:
<span>Face value $4,530,
discount rate 7.2%,
time 125 days
Discount on Simple Discount note:
Discount = Maturity Value * discount rate * term
Discount = 4,530 * 0.072 * 125/360
Discount = 113.25
Proceeds for the simple discount note
Proceeds = Maturity Value - Discount
Proceeds = 4,530 - 113.25
Proceeds = 4,416.75
The proceeds for the simple discount note is $4,416.75</span>
Answer:
Table 1
Step-by-step explanation:
For a function to be linear, equal changes in x must correspond to equal changes in y.
In all tables, the x values increase by 1, so all changes in x in all 4 tables are 1.
If a function is linear, then all changes in y must be equal.
Table 1:
5 - 6 = -1
4 - 5 = -1
3 - 4 = -1
All changes in y are equal, so the first table is linear.
Table 2:
4 - 3 = 1
6 - 4 = 2
Two differences in y are different, so table 2 is not linear.
Table 3:
6 - 7 = -1
5 - 6 = -1
3 - 5 = -2
Not all differences in y are equal, so table 3 is not linear.
Table 4:
4 - 2 = 2
5 - 4 = 1
Not all differences in y are equal, so table 3 is not linear.
The only table that has equal differences in y corresponding to equal differences in x is Table 1, so only Table 1 shows a linear function.
