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NemiM [27]
3 years ago
7

HELP ME :) please .....

Mathematics
2 answers:
iren [92.7K]3 years ago
8 0
2a^2b^5 is the answer ....
Fantom [35]3 years ago
7 0
They all have a common factor of 2 a^2 and b^5, so the answer is:
2 a^2 b^5
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4x-y=1 inslope intercept form please show work
shutvik [7]

Answer:

y = 4x - 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 4x - y = 1 into this form

add y to both sides

4x = y + 1 ( subtract 1 from both sides )

4x - 1 = y

y = 4x - 1 ← in slope-intercept form


5 0
3 years ago
Simplify these expressions<br> 2a + 5a <br> 12x-3x<br> 3p+2p-p
Novosadov [1.4K]

Step-by-step explanation:

1.solution

=2a+5a

=7a

2.solution

=12x-3x

=9x

3.solution

=3p+2p-p

=5p-p

=4p

Hope it helps you.

6 0
3 years ago
Read 2 more answers
If f x = 7x<br><br> 2 − 4x − 10, then f −3 =?
Schach [20]

Answer:

f(x)=xy3 -4xy2 -7x+10

Step-by-step explanation:

the xy3 and xy2 means x to the 3rd power and x to the second power

7 0
3 years ago
Chris shoots an arrow up into the air. The height (in feet) of the arrow is given by the function h(t) = - 16t2 + 64t + 112 wher
iris [78.8K]

Answer:

After 2 seconds

Step-by-step explanation:

First step is find an equation of velocity:

h(t)=-16t2+64t+112. The velocity function is derivated from position function, so we should do that.

v(t)= h´(t)= -16*2*t+64 ⇒ v(t)= -32t+64.

Now we know the arrow reach the maximun height when this velocity is equal to zero when t>0.

0=-32t+64 ⇒ 32t=64, split each member for 32 ⇒ \frac{32t}{32}=\frac{64}{32}

t=2. That means after 2 sec. the arrow reach the maximum height

6 0
3 years ago
Read 2 more answers
The graph of a sinusoidal function intersects its midline at (0,5) and then has a maximum point at (\pi,6)
Natalija [7]
First, let's use the given information to determine the function's amplitude, midline, and period. 

Then, we should determine whether to use a sine or a cosine function, based on the point where x=0.

Finally, we should determine the parameters of the function's formula by considering all the above.
     
                      Determining the amplitude, midline, and period 

The midline intersection is at y=5 so this is the midline. 

The maximum point is 1 unit above the midline, so the amplitude is 1. 

The maximum point is π units to the right of the midline intersection, so the period is 4 * π.
 
                            Determining the type of function to use 

Since the graph intersects its midline at x=0, we should use thesine function and not the cosine function. 

This means there's no horizontal shift, so the function is of the form -

a sin(bx)+d

Since the midline intersection at x=0 is followed by a maximumpoint, we know that a > 0.

The amplitude is 1, so |a| = 1. Since a >0 we can conclude that a=1. 

The midline is y=5, so d=5. 

The period is 4π so b = 2π / 4π = 1/2 simplified. 

f(x)1 sin   (\dfrac{1}{3}x) +5  = Solution
8 0
3 years ago
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