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laiz [17]
3 years ago
13

Need two examples using this chart. PLEASE!

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
8 0

Answer:

We will use Descarte's Rule to solve the following question:

  • Work area to determine possible positive real roots:

It says that the number of sign changes in the function f(x) tells the maximum number of positive roots that could exist.

  • Work area to determine possible negative real roots:

Similarly the number of sign changes in the function f(-x) tells the maximum  number of negative roots that could exist.

Now let us consider a example as:

<h3>1) f(x)=x^3-x^2+5</h3>

We know that the total number of zeros of a polynomial function is always equal to the degree of the polynomial.

This is a polynomial function of degree 3 hence it has total 3 zeros.

Now f(x) has total 2 sign changes first from + to - and then from - to +.

Hence atmost 2 positive real zeros are possible.

Also f(-x)=-x^3-x^2+5

This function has only one sign change i.e. from - to +.

Hence atmost 1 negative real roots are possible.

Also on solving the cubic equation we got that we have one real zeros and 2 complex zeros.

In table we could write as:

<u>total zeros:</u>                 3    (-1.4334 ,  1.2167-1.4170 i ,  1.2167+1.4170 i)

<u>No. of positive : </u>          None

<u>real zero</u>

<u>No. of negative :</u>          1  (-1.4334)

<u>real zero</u>

<u>Complex zero :</u>              2  (1.2167-1.4170 i and  1.2167+1.4170 i)

<h3>2) f(x)=x^4+x^3-1</h3>

This is a polynomial function of degree 4 hence it has total 4 zeros.

Now f(x) has total 1 sign changes first from + to - .

Hence atmost 1 positive real zeros are possible.

Also f(-x)= x^4-x^3-1

This function has only one sign change i.e. from + to -.

Hence atmost 1 negative real roots are possible.

Also on solving the cubic equation we got that we have two real zeros and 2 complex zeros.

In table we could write as:

<u>total zeros:</u>                  4    (-1.3803, 0.81917 , -0.21945-0.91447 i ,    

                                                 ,   -0.21945+0.91447 i)    

<u>No. of positive : </u>          1 (0.81917)

<u>real zero</u>

<u>No. of negative :</u>          1  (-1.3803)

<u>real zero</u>

<u>Complex zero :</u>              2 (-0.21945-0.91447 i , -0.21945+0.91447 i)


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