Answer:
96 ways
Step-by-step explanation:
Let´s call flags of countries from Africa as A₁, A₂, A₃, A₄, and from Europe as E₁, E₂, E₃ and E₄
We have to display the flags always beginning with one flag from Africa let´s take A₁
For that flag, we have 4! possibilities Then 4! is:
4*3*2*1 = 24
As we have 4 different Flags from Africa, we will have
4*24 = 96 possibilities
15/4 would be your answer
Answer:
1) 2x-5 2) -10/x^2
Step-by-step explanation:
Use power rule and constant rule for the first one:
1) f(x)=x^2-5x^1+1 (x^n)'=nx^(n-1) and (c)'=0
f'(x)=2x^1-5(1)x^0+0
f'(x)=2x-5(1) x^0=1
f'(x)=2x-5
Use just power rule for last one after a rewrite
2) f(x)=10/x
f(x)=10x^(-1) now use power rule
f'(x)=-10x^(-2) =-10/x^2
The range is from 18 to 2 (greatest to least).
2 < x < 18
see attachment
if you move the whole triangle up 4 units and to the left 3 units without rotating or dialating it, then each point should move up 4 units and 3 units to the left
find the distance between the first point and the translated point
if we draw out the path, we can see that the path makes 2 legs of a right triangle. the distance between the start and end is the hypotonuse
the 2 legs are length 3 and 4
by the pythagorean theorem, d²=3²+4²
d²=9+16
d²=25
d=5
so the distance between any 2 points on the original triangle and the translated triangle is 5 units
