Hi I am here to help the answer is 46-90
Range is the y values or ouputs
domain is inputs or x vvalues
we can use any x value
but at a certain y value, w can't go below that
find thatminimum
find the vertex
for
ax^2+bx+c
the x value of the vertex is
-b/2a
plug that in to the equaiton to get the y value
-b/2a=-(-6)/(2*2)=6/4=3/2
plug that in
2(3/2)^2-6(3/2)-9
2(9/4)-9-9
9/2-18
4.5-18
-13.5
domain=all real numbers
range=from -13.5 to positive infinity
Answer: See below
Step-by-step explanation:
<u>Area of the square</u> = l*w = 11*11 = 121
<u>Area of the circle</u> = pi r^2 = pi*1^2 = 3.142
<u>Part A</u>
P(hitting the circle) = 3.142 / 121 = 0.026 which is closer to 0.
<u>Part B</u>
P(hitting the outside portion) = 1 - 0.026 = 0.974 which is closer to 1.
You have to find a common denominator for both fractions. I chose the denominator to be 10, so the 1/2 will become 5/10, and 1/5 will become 2/10.
Subtract 5/10 from 2/10. You will get -3/10.
Answer: -3/10
You can check your answer by solving 1/2-3/10=1/5 to see if it is true. (It is:)
Answer:
14/24 And 21/36
Step-by-step explanation:
Just multiply the fractions by any number. In this case 2 and 3.
