You use the formula below...,
Angle theta = cos^-1 [scalar product of the two vectors ÷ multiplication of their moduli]
For example...the angle between
(2i + 3j) and (4i + 5j)
Angle theta = cos^-1 [( 2(4) + 3(5))÷((square root of (2^2 + 3^2))×(square root of (4^2 + 5^2))
Angle theta = cos^-1 [ 23 ÷ ((square root of(13)) × (square root of (41)]
Angle theta = 5°
Answer:
here
Step-by-step explanation:
it is basically a sector , use the area formula i.e.
[(theta)/360]*πr^2
Answer:
38
Step-by-step explanation:
I did this to get 47.5 as the answer not 47 im not sure why but i did (61-7+7×1/2)+17 using the PEMDAS please excuse my dear aunt sally
parenthesis exponents multiply divide add subtract
Answer:
31.75 round it off to 32 pages per day
Step-by-step explanation:
254/8=31.75 but you cant but a decimal so its 32
