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3 years ago

Please help i need answer for test

Mathematics

1 answer:

Korvikt [17]3 years ago

6 0

Answer:

He did the complete opposite of what he needed to do

Step-by-step explanation:

The error is that when you need to find x - intercept, you need to replace the value of y with zero, not the y value.

Cause otherwise, what he did here is to find the y - intercept

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)

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What is the equation of the line that passes through the points (1, −10) and (−4, −7)?

nignag [31]

Hi there! :)

First, let's find the slope using this formula:

m= $\frac{y2-y1}{x2-x1}$

m= $\frac{-7-(-10)}{-4-1} \\\frac{-7+10}{-5} \frac{3}{-5} =-\frac{3}{5}$

Now, use the Point-Slope formula:

y-y1=m(x-x1)

y-(-10)=-3/5(x-1)

y+10=-3/5x+3/5

y=-3/5x+3/5-10

y=-3/5x-9.4

Hope this helps..

~Just an emotional teen who listens to "Try Everything"

$SilentNature$

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2 years ago

Silvio wants to find the perimeter of quadrilateral ABCD. He begins by computing the length of side AB using the distance formul

saveliy_v [14]

Answer:

Step-by-step explanation:

AB = √(-4)² + (-3)²

AB = √ 16 + 9

AB = √ 25

AB = 5

AD = 4 ; DC = 4 ; BC = 7

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2 years ago

I need help. this is the problem x^2/3+10=7x^1/3

Arlecino [84]

$\it x^{\frac{2}{3}}+10=7x^{\frac{1}{3}} \Leftrightarrow (x^{\frac{1}{3}})^2-7x^{\frac{1}
 {3}} +10=0 
\\\;\\
We\ note\ x^{\frac{1}{3}} =t \ \ and \ the \ equation \ will \ be:
\\\;\\
t^2-7t+10 = 0 \Leftrightarrow t^2 -2t-5t+10=0 \Leftrightarrow t(t-2) -5(t-2)=0$

$\it \Leftrightarrow (t-2)(t-5)=0 
\\\;\\
t-2=0 \Rightarrow t=2 \Rightarrow x^{\frac{1}{3}}=2 \Rightarrow (x^{\frac{1}{3}})^3 =2^3 \Rightarrow x = 8
\\\;\\
t-5=0 \Rightarrow t=5 \Rightarrow x^{\frac{1}{3}}= 5 \Rightarrow (x^{\frac{1}{3}})^3 = 5^3 \Rightarrow x = 125$

S = {8; 125}

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3 years ago

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The air plane is rising so the change in elevation is +1000 feet. The temp dropped and is -20 degrees fahrenheit.

1 degree per 50 ft

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Step-by-step explanation:

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Here,

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