Given that 
, and 
, this first step can be to make the equations equivalent to one another. As you can see, each equation is equal to a constant, e. Therefore, we can conclude that the equations can be equal to one another as well ( transitivity ).
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Nice and simple question we have here! The step that can be used to find the solution should be 
.
16, Rewrite 64 as 4 to the 3 power, apply the power rule and multiply the exponents, cancel the common factor and rewrite the equation and get 4 to the 2 power, which is equal to 16!
I'm pretty sure its the second one
The function given is a line with one zero at the center (0,0)
