A= 2 WL+ 2 LH+ 2 HW.
W= width
L= length
H= height
Consider the function

, which has derivative

.
The linear approximation of

for some value

within a neighborhood of

is given by

Let

. Then

can be estimated to be

![\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B63.97%7D%5Capprox4-%5Cdfrac%7B0.03%7D%7B48%7D%3D3.999375)
Since

for

, it follows that

must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function

. This means the estimated value is an overestimation.
Indeed, the actual value is closer to the number 3.999374902...
The average of a set of data is equal to the sum of the values divided by the number of data present. So, if we have three numbers, the average would be:
let x, y and z represent the three numbers
average = x + y + z / 3 = 45
Two number are equal in value, so let x = y. Substituting the value to the expression of average,
45 = x + x + z / 3
45 = 2x + z / 3
It said that the last number is 89 so z is equal to 89.
45 = 2x + 89 / 3
135 = 2x + 89
46 = 2x
x = 23
Therefore, the two numbers are both 23.
Answer:
29.97 square feet
Step-by-step explanation:
Given
The length of rectangle = 9 ft
The width of rectangle = 40 in
We have to bring the length and width in same unit. As the area is required in square feet so we will convert width in feet
The width will be divided by 12 to be onverted into feet
So,
Width = 40/12 = 3.33 feet
Now
Area = Length * width
= 9 * 3.33
= 29.97 square feet ..
Hope it can help u!!!!!!!