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3 years ago

How much water should be added to 6 gallons of pure acid in order to obtain the 24% acid solution?

Mathematics

2 answers:

Helen [10]3 years ago

6 0

Answer:

19 gallons

Step-by-step explanation:

Let x gallons be the amount of water which should be added to 6 gallons of pure acid in order to obtain the 24% acid solution.

Amount of water = x gallons

Amount of pure acid = 6 gallons

Amount of acid solution = x + 6 gallons

Amount of acid in acid solution = 24%

So, there are $0.24(x+6)$ gallons of acid in acid solution.

Hence,

$0.24(x+6)=6$

Solve this equation. Multiply it by 100:

$24(x+6)=600\\ \\24x+144=600\\ \\24x=600-144\\ \\24x=456\\ \\x=19\ gallons$

8_murik_8 [283]3 years ago

3 0

Answer:

19 gallons

Step-by-step explanation:

19 gallons

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