1634/19=86. Hope this helps
The median is 11, so 11 is part of the data set. We have an odd number of values (5) which is why the median is part of the data set.
The mode is 12. The value 12 shows up the most times. Let's say it shows up twice. So far the data set is {11, 12, 12}
Let's introduce two more numbers x and y
The new data set is {x, y, 11, 12, 12}
Add up the five values and then divide by 5. We want this result to be equal to 10
(x+y+11+12+12)/5 = 10
(x+y+35)/5 = 10
x+y+35 = 10*5
x+y+35 = 50
x+y = 50-35
x+y = 15
So we don't know what x or y is, but we know that they must add to 15. So all you have to do is list two numbers that add to 15. One such pair is x = 6 and y = 9. Another pair is x = 7 and y = 8. There are infinitely many possibilities if you can use any real number.
So one possible set is {6, 9, 11, 12, 12}
Another possible set is {7, 8, 11, 12, 12}
Answers
1.) would be A.) y = 2x + 3
2.) would be graph B) the graph looks a little blurry so it could also be C) just a heads up but I’m almost positive it’s B
Hey there! :)
Answer:
C.
Step-by-step explanation:
For a graph to have a change in amplitude, there must be a coefficient in front of the equation, or the 'a' value.
Recall that the transformation form of a trigonometric graph is:
y = ±a(cos(b(x-h))+k
Where 'a' is the amplitude
'b' changes the period
'h' is a horizontal shift
'k' is a vertical shift
We can look at each choice and eliminate:
A. There is only a coefficient of -1 in front of the equation, which simply results in a reflection over the x-axis. This is incorrect.
B. This equation contains a b value of 2. This changes the period of the graph, not the amplitude. This is incorrect.
C. This equation contains a coefficient, or 'a' value of -2. The amplitude is changed by a factor of 2. This is correct.
D. This graph only contains a vertical shift of 1 unit up. This is incorrect.
Therefore, C is the correct answer.
Answer:
3x^2+12x+12
Step-by-step explanation:
i think you just sub in x+2 into 3x^2
