If the maximum is 20 and the minimum is 6 write a absolute value equation for the two solutions
1 answer:
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Alejandro makes an error in the first steps he divides 8 by 5 which is incorrect he has to divide 5 by 8, and in the second step, he does not multiply the term by 100 and it can be determined by using fraction or percentage.
<h2>Given that,</h2>Alejandro uses the steps below to convert 5/8 to a percent.
8 divided by 5 = 1.6.,
1.6 = 160 percent
<h3>We have to determine,</h3>Which best explains Alejandro's error?
<h3>According to the question,</h3>Alejandro uses the steps below to convert 5/8 to a percent.
8 divided by 5 = 1.6.,
1.6 = 160 percent
The division was computed incorrectly.
The division was completed in the incorrect order. The decimal was moved to the right too many times.
The decimal was moved to the right instead of the left.
Alejandro uses the steps below to convert 5/8 to a percent.
To convert 5/8 into percentages following all the steps given below.
- Step1; Firstly 5 is divided by 8,
- Step2; To convert 0.625 into percentage multiplied by 100,
Hence, Alejandro makes an error in the first steps he divides 8 by 5 which is incorrect he has to divide 5 by 8, and in the second step, he does not multiply the term by 100.
For more details about the Equation refer to the link given below.
We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d
we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor
p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)
therefor
p=d(x+4) and
x^2-5x+6=d(x-2)
we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub
p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d
we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor
p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)
therefor
p=d(x+4) and
x^2-5x+6=d(x-2)
we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub
p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)