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12345 [234]
3 years ago
14

Is 70 thousand written in standard form or word form??

Mathematics
2 answers:
lozanna [386]3 years ago
8 0
The answer is standard form
Naddik [55]3 years ago
4 0
It was written in word form.
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The circumference A of a circle varies directly with its radius. A circle with a radius of 4 has a circumference of about 25.1 i
horsena [70]

Answer:

25.1 in.2.

Step-by-step explanation:

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3 years ago
Choose the expanded form of this expression 4(1/4 a + b - 6)
zalisa [80]

Answer:

a+4b-24

Step-by-step explanation:

4(1/4a+b−6)

=(4)(1/4a+b+−6)

=(4)(1/4a)+(4)(b)+(4)(−6)

=a+4b−24

3 0
3 years ago
Please help with this?
frez [133]

7p3 = 210
8 0
3 years ago
Can she get some help
Artemon [7]

Answer:

-55

Step-by-step explanation:

the sqeuence seems to be subtracting by 2 everytime.

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the answer will be 27*-2(-54) -1(because we start at -1 , not 0)

5 0
3 years ago
Read 2 more answers
Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?
Yanka [14]

Answer:

Step-by-step explanation:

\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.

\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\

(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+  \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.

8 0
1 year ago
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