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Fudgin [204]
2 years ago
9

Simpify this expresion 7+5h+2h+7h2–2h2

Mathematics
1 answer:
yarga [219]2 years ago
6 0

Answer:

5h^2 + 7h + 7

Step-by-step explanation:

We can simplify this expression by combining like terms.

To combine like terms, we are looking for terms that share the same variable and exponent.

First, we can see that the terms 7h^2 and -2h^2 share the same variable (h) and the same exponent (2).

7 - 2 = 5

This simplifies to 5h^2.

Next, we can see that 5h and 2h share the same variable (h) and the same exponent (1) so we can add these.

5+2=7

This simplifies to 7h.

Lastly, we can see that we just have 7, no more terms with the same variable (none). So this is 7.

Adding up all the terms in standard form (ax^2 + bx + c), we get 5h^2 + 7h + 7.

Hope this helped!

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Are the following ratios equivalent? Why or why not? 4:5 and 16:20
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Answer:

Equivalent

Step-by-step explanation:

4:5      multiply both sides by 4  to get    16:20    

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2 years ago
Point M is located at (3,7). If point M is translated 2 units to the left and 4 units down, what are the coordinates of M Q1 (-1
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The answer is simply (1,3) just subtract 2 from 3 and 4 from 7.
3 0
3 years ago
Read 2 more answers
Solve for x.
denis-greek [22]

Answer:

\frac{3\±\sqrt{3}}{3}

Step-by-step explanation:

Whe have the function 3x^2-6x+2=0

To solve this equation we must factor.

To factor, we need to find the points where the function is equal to zero. So we use the quadratic formula

\frac{-b\±\sqrt{b^2-4ac}}{2a}

Where:

a = 3

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Then

\frac{-(-6) + \sqrt{(-6)^2-4(3)(2)}}{2(3)} = \frac{3+\sqrt{3}}{3}\\\\and\\\\\frac{-(-6) - \sqrt{(-6)^2-4(3)(2)}}{2(3)}= \frac{3-\sqrt{3}}{3}

finally the correct answer is  \frac{3\±\sqrt{3}}{3}

5 0
2 years ago
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Jarrett's puppy weighed 3 3/4 ounces at Birth. At 1 week old, the puppy weighed 5 1/8 ounces. At 2 weeks old, the puppy weighed
Ad libitum [116K]

Answer:  The answer is 7\dfrac{7}{8} ounces.

Step-by-step explanation: Given in the question the weight of Jarrett's puppy at birth, one week old and 2 weeks old are as follows:

b_0=3\dfrac{3}{4}=\dfrac{15}{4}~\textup{ounces},\\\\\\b_1=5\dfrac{1}{8}=\dfrac{41}{8}~\textup{ounces},\\\\\\b_3=6\dfrac{1}{2}=\dfrac{13}{2}~\textup{ounces}.

We can see that

b_1-b_0=b_2-b_1=\dfrac{11}{8}.

So, the weight of the baby will make an arithmetic progression with first term 'a' and common difference 'd' as follows:

b_0=\dfrac{15}{4},~~d=\dfrac{11}{8}.

Thus, the weight of the puupy after 3 weeks will be

b_3=b_0+3\times d=\dfrac{15}{4}+3\times\dfrac{11}{8}=\dfrac{30+33}{8}=\dfrac{63}{8}=7\dfrac{7}{8}~\textup{ounces}.

5 0
3 years ago
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