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Ganezh [65]
3 years ago
6

Don’t know much about geometry

Mathematics
1 answer:
Mariana [72]3 years ago
7 0

Answer:

Step-by-step explanation:

J is a tangent to the circle and it is at right angle,

So applying Pythagorean theorem

HK² = KJ² + HJ²

HK² = 8²+ 15²

HK² = 64 + 225

HK² = 289

HK = √289

HK = 17 mi

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The coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)

Step-by-step explanation:

Square JKLM with vertices

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We have to determine the answer for the image J' of the point (1, -3) when we rotate the point by 90° counterclockwise, we need to switch x and y, make y negative.

In other words, the rule to rotate a point by 90° counterclockwise.

P(x, y) → P'(-y, x)

As we are given that J(1, -3), so the coordinates of J' will be:

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Therefore, the coordinates of J' when rotating by 90° counterclockwise will be:  J'(3, 1).

When the point is rotated by 90° clockwise, we need to switch x and y, make x negative.

In other words, the rule to rotate a point by 90° clockwise.

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As we are given that J(1, -3), so the coordinates of J' will be:

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Therefore, the coordinates of J' when rotating by 90° clockwise will be:  J'(-3, -1)

3 0
2 years ago
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