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3 years ago

Don’t know much about geometry

Mathematics

1 answer:

Mariana [72]3 years ago

7 0

Answer:

Step-by-step explanation:

J is a tangent to the circle and it is at right angle,

So applying Pythagorean theorem

HK² = KJ² + HJ²

HK² = 8²+ 15²

HK² = 64 + 225

HK² = 289

HK = √289

HK = 17 mi

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Consider the given density curve.

Gemiola [76]

Answer:

11 is best answer for it ....,..........

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2 years ago

1/5+1/7+3/21 the answer is

inessss [21]

Answer:

Step-by-step explanation:

We need to get all the fractions with a common denominator before we can solve the problem.

The only fractions that have a common multiple are 1/7 and 3/21, so we'll add these first and then add 1/5.

1/7 = 3/21

Add

$\frac{3}{21} + \frac{3}{21} =\frac{6}{21}$

6/21 = 30/105

1/5 = 21/105

$\frac{30}{105} + \frac{21}{105} = \frac{51}{105}$

Simplify

$\frac{51}{105} / \frac{3}{3} =\frac{17}{35}$

<h3>ANSWER: 17/35</h3>

I'm always happy to help :)

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3 years ago

Question 12

klasskru [66]

Mr. Jones's prescription calls for 1.04 tablets per day. Based on this information, how many tablets should Mr. Jones take per day? a) 1.25 O b) 1.5 c) 10 d) 2

3 0

2 years ago

The perimeter of a rectangular field is 360yd. The length is 20yd longer than the width. Find the dimensions

Tju [1.3M]

If P=360, then 360yd / 4 sides = 90yds each side. Now that it is a rectangle, the Length should be more than the width, so if the length is 20yds more than the width, do 90 - 20 two times, Width= [ (90yds - 20yds)*2 ]

To sum things up, Length = 110; Width = 70. | 110*2 = 220, 70 * 2 = 140, 220+140 = 360.

5 0

3 years ago

Read 2 more answers

A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0

4 years ago