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3 years ago

5

Me. Moss draws a triangle with a base of 12 cm and a height of 5.6 cm. If she colors the space inside the triangle, what is the

area she colors?

2 answers:

zalisa [80]3 years ago

8 0

Sorry about the scratches

igor_vitrenko [27]3 years ago

5 0

She colors 33.6 sq cm

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Can I get some help on this

nordsb [41]

Answer: Choice C

The vertical asymptote at x = -4 tells us that -4 is not part of the domain. This only applies to 1/(x+4). If we plug in x = -4, we get...

f(x) = 1/(x+4)
f(-4) = 1/(-4+4)
f(-4) = 1/0
f(-4) = undefined; because of the division by zero error

The value x = -4 is allowed in the other answer choices.

5 0

3 years ago

5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim

Ne4ueva [31]

Answer:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

$S_p=2.940$

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

$df=60+72-2=130$

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

$n_1 =60$ represent the sample size for people who used a self service

$n_2 =72$ represent the sample size for people who used a cashier

$\bar X_1 =5.2$ represent the sample mean for people who used a self service

$\bar X_2 =6.1$ represent the sample mean people who used a cashier

$s_1=3.1$ represent the sample standard deviation for people who used a self service

$s_2=2.8$ represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

And t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

System of hypothesis

Null hypothesis: $\mu_1 \geq \mu_2$

Alternative hypothesis: $\mu_1 < \mu_2$

This system is equivalent to:

Null hypothesis: $\mu_1 - \mu_2 \geq 0$

Alternative hypothesis: $\mu_1 -\mu_2 < 0$

We can find the pooled variance:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

And the deviation would be just the square root of the variance:

$S_p=2.940$

The statistic is given by:

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

The degrees of freedom are given by:

$df=60+72-2=130$

And now we can calculate the p value with:

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0

3 years ago

Plz help with number 1

Trava [24]

In an isosceles triangle, the base angles are congruent. The third angle is called the vertex angle.

Here, the vertex angle is <A.

Therefore, m<C = m<B.

m<A = 3m<B + 20

m<A + m<B + m<C = 180

3m<B + 20 + m<B + m<B = 180

5m<B + 20 = 180

5m<B = 160

m<B = 32

m<C = m<B = 32

Answer: m<C = 32 deg

4 0

3 years ago

Select the correct answer. What is the solution to this equation? A. B. C. D.

amm1812

Answer:

We do not have any problem to solve?

Step-by-step explanation:

3 0

2 years ago

PLEASE HELP ILL MAKE YOU BRAINLIEST Which of the following ordered pairs should be tested to determine which side to shade when

ArbitrLikvidat [17]

Answer:

That would be option C.

Step-by-step explanation:

I literally just took the quiz and got it right.

8 0

3 years ago