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Tasya [4]
3 years ago
7

If =250, then 50% of n equals

Mathematics
2 answers:
saul85 [17]3 years ago
8 0
The answer is 125 :)
qwelly [4]3 years ago
5 0

If n=250, then 50% of n can also be described as n divided by 2.

50% of n = 250/2 = 125

answer: 125

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The company has 5 employees, who earn a total of $1,000 each working day. They are paid each Monday for their work in the five-d
Angelina_Jolie [31]

5 x 1,000 = 5,000 a week or 20,000 a month.

take 1,000 divide by 5 and you get 200 a day


$400 on december 31


6 0
3 years ago
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A coordinate plane with a line passing through the points (negative 4, negative 5) and (1, negative 1).
Ksju [112]

Answer:

4x - 5y - 9 = 0

\frac{9}{4}

\frac{-9}{5}

Step-by-step explanation:

The equation of a straight line passing through the points (-4,-5) and (1,-1) is given by \frac{y - (-5)}{-5-(-1)} =\frac{x-(-4)}{-4-1}

⇒ \frac{y+5}{-4} =\frac{x+4}{-5}

⇒ 5y + 25 = 4x + 16

⇒ 4x - 5y - 9 = 0 ....(1) (Answer)

Now, this above equation can be represented as

\frac{x}{\frac{9}{4} } + \frac{y}{\frac{-9}{5} } =1

Therefore, the x-intercept is \frac{9}{4} (Answer)

And the y-intercept is \frac{-9}{5}. (Answer)

7 0
3 years ago
Read 2 more answers
Use the Commutative Property to write an expression equivalent to –5d + 1/2.
Jet001 [13]

Answer: 12-5d

because all you do is flip the expression

7 0
3 years ago
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Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3
aliina [53]

Answer:

C) more than the absolute value of the critical value, we can conclude that the average monthly rate for an assisted-living facility is not equal to $3,300.

Step-by-step explanation:

Hello!

Interest hypothesizes is " the average monthly rate for one-bedroom assisted-living facility is equal to $3300" symbolically: μ = 3300

The study variable is:

X: Monthly rate for a one-bedroom assisted-living facility.

Since there is no information about the distribution of the variable, to be able to study the population mean, I'll assume that the variable has a normal distribution.

The hypothesis is:

H₀: μ = 3300

H₁: μ ≠ 3300

α: 0.05

The statistic to use, considering that there is no known population information and the sample size, is a Student t:

t= <u> X[bar] - μ </u> ~t_{n-1}

       S/√n

n= 12

X[bar]= $3690

S= $530

Using the sample data, calculate the statistic value:

t= <u> 3690 - 3300 </u> = 2.549

       530/√12

The rejection region for this test is two-tailed, with critical values:

t_{n-1; \alpha /2} = t_{11; 0.025} = -2.201

t_{n-1;1-\alpha /2} = t_{11; 0.975} = 2.201

The decision rule is:

Reject the null hypothesis if t ≤ -2.201 or if t ≥ 2.201

Not reject the null hypothesis if -2.201 < t < 2.201

Since the calculated value (2.549) is greater than the right critical value (2.201) the decision is to reject the null hypothesis.

With a signification level of 5%, there is enough evidence to reject the null hypothesis. This means that the population mean of the monthly rate for a one-bedroom assisted living facility is different from $3300.

I hope it helps!

7 0
3 years ago
Simplify the following expression 7a + 5b - 2a + b
Papessa [141]
5a+6b would be the simplified answer
7 0
1 year ago
Read 2 more answers
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