Answer:
Jenny save 4 times
for the month
Step-by-step explanation:
Given Jenny has saved
over the last 12 months.
She saved either
or
a month.
Let the number of months to save
be x
Let the number of months to save
be y
Total period is 12 month.
![x+y=12 \ \ \ \ equation\ 1](https://tex.z-dn.net/?f=x%2By%3D12%20%5C%20%5C%20%5C%20%5C%20equation%5C%201)
Jenny has saved $3,800 over the last 12 months.
![250x+350y=3800](https://tex.z-dn.net/?f=250x%2B350y%3D3800)
Dividing both side from 50 we get,
![\frac{250}{50}x+\frac{350}{50}y= \frac{3800}{50}](https://tex.z-dn.net/?f=%5Cfrac%7B250%7D%7B50%7Dx%2B%5Cfrac%7B350%7D%7B50%7Dy%3D%20%5Cfrac%7B3800%7D%7B50%7D)
![5x+7y=76 \ \ \ \ equation\ 2](https://tex.z-dn.net/?f=5x%2B7y%3D76%20%5C%20%5C%20%5C%20%5C%20equation%5C%202)
Now Multiplying equation 1 by 5 we get,
![5\times(x+y)=5\times 12\\5x+5y=60\ \ \ \ equation \ 3](https://tex.z-dn.net/?f=5%5Ctimes%28x%2By%29%3D5%5Ctimes%2012%5C%5C5x%2B5y%3D60%5C%20%5C%20%5C%20%5C%20equation%20%5C%203)
Now Subtracting Equation 3 by equation 2 we get,
![(5x+7y=76)-(5x+5y=60)\\2y=16\\y=\frac{16}{2}= 8](https://tex.z-dn.net/?f=%285x%2B7y%3D76%29-%285x%2B5y%3D60%29%5C%5C2y%3D16%5C%5Cy%3D%5Cfrac%7B16%7D%7B2%7D%3D%208)
Substituting the value of y in equation 1 we get,
![x+y=12\\x+8=12\\x=12-8\\x=4](https://tex.z-dn.net/?f=x%2By%3D12%5C%5Cx%2B8%3D12%5C%5Cx%3D12-8%5C%5Cx%3D4)
∴ Jenny save 4 Months of
and 8 Months of
in a 12 month duration