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Fudgin [204]
3 years ago
7

How to model the problem

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0
Change 5/3 to 15/9. Then add 15 + 17 and put it over 9. 32/9
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2(x + 2) + 3z = 2(x + 1) +1
Oxana [17]

Answer:

Answer:x=

−3z−1

0

Step-by-step explanation:x=

Step 1: Add -2x to both sides.

2x+3z+4+−2x=2x+3+−2x

3z+4=3

Step 2: Add -3z to both sides.

3z+4+−3z=3+−3z

4=−3z+3

Step 3: Add -4 to both sides.

4+−4=−3z+3+−4

0=−3z−1

Step 4: Divide both sides by 0.

0

0

=

−3z−1

0

x=

−3z−1

0

6 0
3 years ago
Read 2 more answers
Find Integrating Fector: <br> ylogy dx + ( x-logy )dy=0
12345 [234]
Rewrite the ODE as

y\log y\,\mathrm dx+(x-\log y)\,\mathrm dy=0\iff y\log y\dfrac{\mathrm dx}{\mathrm dy}+x=\log y
\dfrac{\mathrm dx}{\mathrm dy}=\dfrac1{y\log y}x=\dfrac1y

so that it is now linear in x. An integrating factor would

\mu(y)=\exp\left(\displaystyle\int\frac{\mathrm dy}{y\log y}\right)=e^{\log(\log y)}=\log y

Multiply both sides by \mu(y) to get

\log y\dfrac{\mathrm dx}{\mathrm dy}=\dfrac1yx=\dfrac{\log y}y
\dfrac{\mathrm d}{\mathrm dy}[x\log y]=\dfrac{\log y}y
x\log y=\displaystyle\int\frac{\log y}y\,\mathrm dy
x\log y=\dfrac12\log^2y+C
x=\dfrac12\log y+\dfrac C{\log y}
4 0
3 years ago
This question please; I’ve done all the others but this one has stumped me :/
vesna_86 [32]
2 way table
       cola  water milk total
boy    12     4     16     32
girl       14    9      5     28
Total    28    13    21    60

5 0
3 years ago
PLEASE HELP ASAP<br> find JL
san4es73 [151]

Answer:

7

Step-by-step explanation:

3 0
3 years ago
Given: mHL =40°, mEV =130°, mVL =110°. Find: m∠EYH.
IgorC [24]

Answer:

<h2>The measure of angle EYH is 25°.</h2>

Step-by-step explanation:

Notice that ray EY is a tangent and ray VY is a secant.

In this case, we use the theorem that states <em>"the angle formed by a tangent and a secant is half of the difference of the intercepted arcs".</em>

In this case, the intercepted arcs are EH  and EV. We know that a whole arc is 360°, so

arc(EH)=360-40-110-130=80

Using the theorem, we have

m\angle EYH=\frac{1}{2}(arc(EV)-arc(EH))=\frac{1}{2}(130-80)=\frac{1}{2}(50)\\   m \angle EYH = 25\°

Therefore, the measure of angle EYH is 25°.

7 0
3 years ago
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