Answer:
Area of parallelogram is given by:
where b is the base and h is the height of parallelogram.
In parallelogram TQRS.
Coordinate of TQRS are;
T(8, 16), Q(4, 4), R(16, 4) and S(20, 16)
Coordinate of T'Q'R'S' are;
T'(2, 4), Q'(1, 1), R'(4, 1) and S'(5, 4)
Find the length of QR and PT:
Using distance(D) formula:
units
Similarly;
For PT:
From the graph:
P(8, 4) and T(8, 16), then
units
In parallelogram TQRS
PT represents the height and QR represents the base of the parallelogram respectively.
then;
Area of parallelogram TQRS =
⇒Area of parallelogram TQRS = unit square.
Now, in parallelogram T'Q'R'S'
Q'R' represents the base and P'T' represents the height of the parallelogram respectively.
here, P'(2, 1)
Find the length of Q'R' and P'T':
units
units
Then;
Area of parallelogram T'Q'R'S' =
Area of parallelogram T'Q'R'S' = unit square.
Now, we have to find the relationship between the areas.
then;
the relationship between the areas of TQRS and T'Q'R'S' is:
