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3 years ago

A polar bear swims 390 meters at a in 150 seconds, what is the speed of the polar bear?

2 answers:

8 0

If a polar bear were to swim 390 meters in 150 seconds, that would mean we have to divide 390 by 150.
The polar bear can swim 2.9 meters a second, or 9 feet, and 6 11/64 inches. (9.5144357 feet a second)

topjm [15]3 years ago

4 0

The answer is 2.6 m/s

The speed (v) is distance (d) through time (t).
v = d/t

We know:
d = 390 m
t = 150 s

v = d/t
v = 390 m / 150s
v = = 2.6 m/s

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2x divided by x+5 less than or equal to 0

coldgirl [10]

It is more than 0, because you cancel the x, and you get 2+5, which is 7

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3 years ago

Tyler has 3 times as many books as Mai.

White raven [17]

Answer:

a. x divided by 3

Step-by-step explanation:

because if Tyler has 3 times more books than Mai, then Mai has 3 times fewer books than Tyler.

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3 years ago

Read 2 more answers

Helpppp 2x-1>5 and 3x-5<19

maria [59]

Answer:

3 < x < 8

Step-by-step explanation:

Solve each part separately

2x - 1 > 5 ( add 1 to both sides )

2x > 6 ( divide both sides by 2 )

x > 3 , that is

3 < x

and

3x - 5 < 19 ( add 5 to both sides )

3x < 24 ( divide both sides by 3 )

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Then putting the two together

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3 years ago

Given that h(x) = |12x - 4| + 6, what is the value of x when h(x) = 4?

Rina8888 [55]

Answer:

No solution

Step-by-step explanation:

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3 years ago

The roof of the Terminal Tower is 709 feet above ground. A window washer dropped a bucket from the edge of the roof. How many se

Masja [62]

Answer:

6.64 seconds

Step-by-step explanation:

Given that:

Distance between roof of the terminal and ground = 709 feet

A bucket was dropped from the roof.

To find:

The time taken by the bucket to hit the ground?

Solution:

Distance traveled, $s$ = 709 feet

Initial velocity of the bucket, $u$ = 0 feet/sec (because initially it was at rest)

Acceleration of the bucket will be equal to acceleration due to gravity i.e.

$g$ or 32.1741 $ft/sec^{2}$

Let the time taken is $t$ seconds.

Formula for distance is given as:

$s = ut+\dfrac{1}{2}at^2$

Putting all the values:

$709 = 0 (t) + \dfrac{1}{2}(32.1741) t^2\\\Rightarrow 1418 = 32.1741 t^2\\\Rightarrow t^2 = 44.07\\\Rightarrow t \approx \bold{6.64\ sec}$

6 0

3 years ago