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3 years ago

Find the nth term of this sequence, 3, 6, 9, 12

Mathematics

2 answers:

Mekhanik [1.2K]3 years ago

6 0

Answer:

a(n) = 3 + 3(n -1)

Step-by-step explanation:

Note that each new term is found by adding 3 to the previous term. The first term is 3 and the common difference is 3. Thus, the formula for the nth term is

a(n) = a(1)+d^(n - 1)

or, in this case,

a(n) = 3 + 3(n -1)

miss Akunina [59]3 years ago

3 0

Answer:

$\large\boxed{\sf n^{th} \ term =3n}}$

Step-by-step explanation:

Find common difference from subtracting any term in the sequence with the previous term.

$\large{\sf 6-3}=3$

Apply nth term formula.

$\large{\sf a_n=a_1+(n-1)d$

$\large{\sf d=3 \ \ a_1=3}$

$\large{\sf a_n=3+(n-1)3$

$\large{\sf a_n=3+3n-3$

$\large{\sf a_n=3n}$

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Here's a problem for the minds-good luck!

Art [367]

Answer:

20%

Step-by-step explanation:

Set up a proportion: $\frac{280}{1400} = \frac{x}{100}$
Cross multiply, then divide: 280 × 100 = 28000, 28000 ÷ 1400 = 20
So, 20% were satisfied with their car

I hope this helps!

8 0

2 years ago

Withint on the number line would apresent -2 1/4 HELP MEEEE PLSSS

DochEvi [55]

Answer:

Answer B

Step-by-step explanation:

Fractions on the Number Line

The number line contains an ordered sequence of the numbers, where the smaller numbers are at the left of the greater numbers.

This means -3 is to the left of -2, which is to the left of -1.

Number -2 1/4 lies between -2 and -3.

The only point lying on that interval is B.

Answer B

5 0

3 years ago

In a survey, the planning value for the population proportion is . How large a sample should be taken to provide a confidence in

tatuchka [14]

Answer:

n=350

Step-by-step explanation:

Notation and definitions

$n$ random sample taken (variable of interest)

$\hat p=0.35$ estimated proportion (value assumed)

$p$ true population proportion

Confidence =0.95 or 95% (value assumed)

Me=0.05 (value assumed)

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: