Which set of data contains two outliers? 113, 115, 103, 114, 109, 111, 119 141, 151, 138, 142, 149, 140, 150 99, 113, 91, 104, 1
daser333 [38]
Answer: 99,113,91,104,109,114,97
Step-by-step explanation:
Got 100% on the quiz :)
Answer: The m ∡KLM is: 130° .
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Explanation:
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(3x − 4) = (4x − 27) ; (Since these are "bisected, congruent angles", they are equal).
⇒ 3x − 4 = 4x − 27 ;
⇒ Subtract "4x" from EACH SIDE of the equation; and add "4" to EACH SIDE of the equation;
⇒ 3x − 4 − 4x + 4 = 4x − 27 − 4x + 4 ;
to get:
⇒ - 1x = -23 ;
⇒ Divide EACH SIDE of the equation by "-1" ; to isolate "x" on one side of the equation; and to solve for "x" ;
⇒ -1x / -1 = -23 / -1 ; to get:
⇒ x = 23;
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To find m ∡KLM :
m ∡ KLM = (3x − 4) + (4x − 27) ;
{Note: Remember: (3x − 4) = (4x − 27) } ;
So, plug in our solved value for "x" ; which is: "x = 23" into one of the expressions for one of the congruent angles.
Let us start with: "(3x − 4)" .
(3x − 4) = 3x − 4 = 3(23) − 4 = 69 − 4 = 65 .
By plugging in our solve value for "x" ; which is: "x = 23" ; into the expression for the other congruent angle, we should get: "65" ;
Let us try:
(4x − 27) = 4x − 27 = 4(23) − 27 = 92 − 27 = 65. Yes!
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So to find m ∡KLM:
(3x − 4) + (4x − 27) = 65 + 65 = 130° .
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Alternate method:
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At the point which we have:
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To find m ∡KLM :
m ∡ KLM = (3x − 4) + (4x − 27) ; and at which we have our solved value for "x" ; which is: "x = 23" ;
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We can simply plug in our known value for "x" ; which is: "23" ; into the following:
m ∡ KLM = (3x − 4) + (4x − 27) = [(3*23) − 4] + [(4*23) − 27] ;
= (69 − 4) + (92 − 7) = 65 + 65 = 130° .
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{Note: Using this method, we determine that each angle is equal; that is, "65° ".}.
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Answer:
T
Step-by-step explanation:
Because the point (3,-5) is simply the point with coordinates (-3,-5) reflected on the y-axis.
Answer:
3.5 in²
Step-by-step explanation:
Given:
Radius (r) = 1.5 in.
Formula for area of half circle = (πr²)/2
Required:
Area of the half circle
Solution:
Plug in the values into the formula for area of half circle.
Thus:
Area = (π × 1.5²)2
= 7.06858347/2
Area = 3.5 in² (nearest tenth)
