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3 years ago

Write the slope intercept form of the equation of the line through the given point with the given slope.

Mathematics

1 answer:

MatroZZZ [7]3 years ago

6 0

Answer:

1) y = 2x-2

2) y = -6/5+1

Step-by-step explanation:

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I could use some help , i really cant do geometry :(

Gelneren [198K]

Answer:

I am not sure but for

CAE it is 65˚

CBD it is 65˚

Step-by-step explanation:

x+40=3x-10

Move the 3x to the other side by subtracting by 3x on both sides

x-3x+40=3x-3x-10

The equation now looks like this:

-2x+40=-10

Move 40 to the other side by subtracting 40 both sides:

-2x+40-40=-10-40

-2x=-50

Divide by -2 on both sides:

-2x/-2=-50/-2

x=25

Since we found out what x is we can replace x in both CAE and CBD:

For CBD: 25+40 is 65

For CAE: 3(25)-10 is 65

5 0

2 years ago

Read 2 more answers

At the start of his race, 86-kg Olympic 100m champion Usain Bolt pushes against the starting block, exerting an average force of

Leviafan [203]

1) Determine the horizontal force, Fx, exerted by the block on Usain

cos(20°) = Fx / F => Fx = F*cos(20) = 1700N*cos(20) = 1597.48 N

2) Determine the Impulse of that force on Usain.

I = F*t = 1597.48N * 0.32s = 511.19 N*s

3) Determine change in momentum of Usain, Δp

Δp = I = 511.19 N*s

4) Find change if velocity

Δp = Δ(mV) = mΔV => ΔV = Δp / m = 511.19 N*s / 86 kg = 5.94 m/s

Given the Usain started from rest, the velocity is ΔV - 0 = 5.94 m/s

Answer: 5.94 m/s

3 0

3 years ago

Solve 0= 2t^3-21t^2+ 40t

sukhopar [10]

$0=2t^3-21^2+40t$
switch sides
$2t^3-21t^2+40t=0$
solve factoring
$t(t-8)(2t-5)=0$
using the zero factor principle
$t=0
$
solve
$t-8=0:t=8$
solve
$2t-5=0:t= \frac{5}{2}$
$t=0,t=8,t= \frac{5}{2}$
Hope this helps

4 0

3 years ago

3/4(5x - 3) + 8 = 17.

Olin [163]

Answer:

x=3

Step-by-step explanation:

8 0

3 years ago

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love history [14]

Answer: