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iren2701 [21]
3 years ago
5

Factor the expression. 20k + 50

Mathematics
2 answers:
Kryger [21]3 years ago
7 0
10 (2k+5) 10 as common
Sloan [31]3 years ago
5 0
20,050 is the answer because you add 20,000 plus 50 and get 20,050
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You want to buy some apples. Look at the scales below.
timofeeve [1]

Answer: no scale

Step-by-step explanation:

3 0
3 years ago
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All the dimensions of a triangle were multiplied by the same factor. If the base of the triangle went from 1 centimeter to 3 cen
timama [110]
The answer is 9.

To calculate this, we will use Galileo's square cube law, used to describe the change of the area or the volume of the shape, when their dimensions increase or decrease. The formula used for change of the area is
A_2= A_1 (\frac{l_2}{l_1} )^{2}
A₂ - the area after the change,
A₁ - the area before the change,
l₂ - the dimension after the change,
l₁ - the dimension before the change.


It is given:
l₁ = 1 cm
l₂ = 3 cm

Let's use this formula for the mentioned triangle:
A_2=A_1( \frac{l_2}{l_1}) ^{2}  =A_1( \frac{3}{1})^{2} =A_1*3 ^{2} =9A_1

Therefore, the area of the triangle was multiplied by 9.
8 0
3 years ago
what is the general form of the equation of a circle with its Center at -2 1 and passing through -4 one
nydimaria [60]

Answer:

x² + y² + 4x - 2y + 1 = 0

Step-by-step explanation:

The equation of a circle is given by the general equation;

(x-a)² + (y-b)² = r² ; where (a,b) is the center of the circle and r is the radius.

In this case; the center is (-2,1)

We can get radius using the formula for magnitude; √((x2-x1)² + (y2-y1)²)

Radius = √((-4- (-2))² + (1-1)²)

             = 2

Therefore;

The equation of the circle will be;

(x+2)² + (y-1)² = 2²

(x+2)² + (y-1)² = 4

Expanding the equation;

x² + 4x + 4 + y² -2y + 1 = 4 subtracting 4 from both sides;

x² + 4x + y² - 2y + 4 + 1 -4 = 0

= x² + y² + 4x - 2y + 1 = 0

4 0
4 years ago
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Solve the two step equation 14=31.7-3×
Tema [17]
14 = 31.7 - 3x    

-17.7 = -3x              <---- I subtracted 31.7 from both sides

5.9 = x       <---- I divided both sides by -3
6 0
3 years ago
Read 2 more answers
Show 2 different solutions to the task.
laila [671]

Answer with Step-by-step explanation:

1. We are given that an expression n^2+n

We have to prove that this expression is always is even for every integer.

There are two cases

1.n is odd integer

2.n is even integer

1.n is an odd positive integer

n square is also odd integer and n is odd .The sum of two odd integers is always even.

When is negative odd integer then n square is positive odd integer and n is negative odd integer.We know that difference of two odd integers is always even integer.Therefore, given expression is always even .

2.When n is even positive integer

Then n square is always positive even integer and n is positive integer .The sum of two even integers is always even.Hence, given expression is always even when n is even positive integer.

When n is negative even integer

n square is always positive even integer and n is even negative integer .The difference of two even integers is always even integer.

Hence, the given expression is always even for every integer.

2.By mathematical induction

Suppose n=1 then n= substituting in the given expression

1+1=2 =Even integer

Hence, it is true for n=1

Suppose it is true for n=k

then k^2+k is even integer

We shall prove that it is true for n=k+1

(k+1)^1+k+1

=k^1+2k+1+k+1

=k^2+k+2k+2

=Even +2(k+1)[/tex] because k^2+k is even

=Sum is even because sum even numbers is also even

Hence, the given expression is always even for every integer n.

3 0
3 years ago
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