Chemical company makes two brands of anti-freeze the first brand is 60% pure anti-freeze and the second brain is 80% pure anti-f
reeze in order to obtain 40 gallons of a mixture that contains 75% pure anti-freeze how many gallons of each brand of antifreeze must be used
1 answer:
Answer:
We have 60% and 80% antifreeze. We need 40 gallons of 75%
We set up 2 equations: where S = 60% and E = 80%
A) S + E = 40
B) .60S + .80E = (.75 * 40) Multiplying A) by -.8
A) -.8S -80E = -32 Then adding this to B:
B) .60S + .80E = 30
-.2S = -2
S = 10
We will need 10 gallons of 60 % antifreeze and according to equation A) we will need 30 gallons of 80% antifreeze.
Source: https://www.1728.org/mixture.htm
Step-by-step explanation:
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Ok so a∈{-3,-1,0}. then just {-3*-1,-1*-1,0*-1} which comes to {3,1,0}
-2.7639320225 is the exact when estimated -3 hope this helped if can pls mark as brainliest have a great day!
Answer:
19 prizes.
Step-by-step explanation:
First add 153 and 37 which is 190. Then divide 190 and 10. Which is 19.
Answer:
60
Step-by-step explanation:
Replace c and d with -5 and 6.
-2*-5*6
-2*-5=10
10*6=60
The expression is equal to 60.
-hope it helps
Answer:
would it be zero because when you try to find the equation its just 0 so it would be y=3
Step-by-step explanation:
as you can see both the points are at 3. so i would say y=3
