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2 years ago

Please do all of these!

1 answer:

7 0

Time/shifts=time per knight

shifts=5

24/5=hours
24/5=20/5+4/5=4+4/5
4/5 times 60=48
4hr and 48 mins
24hr=60*24mins=1440mins
1440/5=288mins per night

A. 4 and 4/5 hour or 24/5 hours
B. 4hr and 48 mins
C. 288 mins

You might be interested in

When planning a date night, you have a choice of 2 types of restaurants: pizza (P) or barbeque (B); a choice of 3 types of movie

enot [183]

Answer:

$S = \{PRC, PRI,PAC,PAI,PDC,PDI,BRC, BRI,BAC,BAI,BDC,BDI\}$

Step-by-step explanation:

Given

$Restaurant = \{P,B\}$

$Movies = \{R,A,D\}$

$Post-movie = \{C,I\}$

Required

List out the sample space

To do this, we simply pick 1 item in each category, without repetition.

So, we have:

$S = \{PRC, PRI,PAC,PAI,PDC,PDI,BRC, BRI,BAC,BAI,BDC,BDI\}$

4 0

2 years ago

Sylvie folds a large piece of paper in half. The fold divides the paper into two equal parts. She folds it in half again. When s

Nikolay [14]

Each time you fold a paper it will double the amount of parts. When you think about it, it's just multiplying by 2 a bunch of times.

One fold is 2 times 1, which is 2.
The second fold is 2 times 2, which is 4.
The third fold is 4 times 2, which is 8.

Using this process, we can simplify that into exponents. If the amount of times you fold is x and the parts double for each fold, then the amount of parts can be represented by:

$2^{x}$

So if the amount of parts is given and we need the amount of folds, just keep doubling until you get to 64. The amount of times you doubled is the number of times Sylvie folded.

Later you will learn that the opposite of an exponent is a logarithm, which would look like this:

$log_{2}(64) = ?$

But don't worry about that yet.

6 0

2 years ago

The CPA Practice Advisor reports that the mean preparation fee for 2017 federal income tax returns was $273. Use this price as t

skad [1K]

Answer:

a) 0.6212 = 62.12% probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean.

b) 0.7416 = 74.16% probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean.

c) 0.8804 = 88.04% probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean.

d) None of them ensure, that one which comes closer is a sample size of 100 in option c), to guarantee, we need to keep increasing the sample size.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The CPA Practice Advisor reports that the mean preparation fee for 2017 federal income tax returns was $273. Use this price as the population mean and assume the population standard deviation of preparation fees is $100.

This means that $\mu = 273, \sigma = 100$

A) What is the probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean?

Sample of 30 means that $n = 30, s = \frac{100}{\sqrt{30}}$

The probability is the p-value of Z when X = 273 + 16 = 289 subtracted by the p-value of Z when X = 273 - 16 = 257. So

X = 289

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{289 - 273}{\frac{100}{\sqrt{30}}}$

$Z = 0.88$

$Z = 0.88$ has a p-value of 0.8106

X = 257

$Z = \frac{X - \mu}{s}$

$Z = \frac{257 - 273}{\frac{100}{\sqrt{30}}}$

$Z = -0.88$

$Z = -0.88$ has a p-value of 0.1894

0.8106 - 0.1894 = 0.6212

0.6212 = 62.12% probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean.

B) What is the probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean?

Sample of 30 means that $n = 50, s = \frac{100}{\sqrt{50}}$

X = 289

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{289 - 273}{\frac{100}{\sqrt{50}}}$

$Z = 1.13$

$Z = 1.13$ has a p-value of 0.8708

X = 257

$Z = \frac{X - \mu}{s}$

$Z = \frac{257 - 273}{\frac{100}{\sqrt{50}}}$

$Z = -1.13$

$Z = -1.13$ has a p-value of 0.1292

0.8708 - 0.1292 = 0.7416

0.7416 = 74.16% probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean.

C) What is the probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean?

Sample of 30 means that $n = 100, s = \frac{100}{\sqrt{100}}$

X = 289

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{289 - 273}{\frac{100}{\sqrt{100}}}$

$Z = 1.6$

$Z = 1.6$ has a p-value of 0.9452

X = 257

$Z = \frac{X - \mu}{s}$

$Z = \frac{257 - 273}{\frac{100}{\sqrt{100}}}$

$Z = -1.6$

$Z = -1.6$ has a p-value of 0.0648

0.9452 - 0.0648 =

0.8804 = 88.04% probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean.

D) Which, if any of the sample sizes in part (a), (b), and (c) would you recommend to ensure at least a .95 probability that the same mean is withing $16 of the population mean?

None of them ensure, that one which comes closer is a sample size of 100 in option c), to guarantee, we need to keep increasing the sample size.

6 0

1 year ago

What is the solution to the equation fraction 1 over 4x = 5?

AVprozaik [17]

$\displaystyle \frac{1}{4x}=5\quad \Big|\cdot 4x\\\\1=20x\quad\Big|:20\\\\x= \frac{1}{20}$

7 0

2 years ago

Find the distance between (-2,-3) and ( 0,3)

12345 [234]

Answer:

(-2,-3)=5

(0,3)=3

Step-by-step explanation:

(-2,-3)=

2+3

(0,3)=

0+3

8 0

2 years ago