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Elanso [62]
3 years ago
5

In the ____ letter style, all components of the letter begin flush with the left margin.

Computers and Technology
1 answer:
Sedaia [141]3 years ago
4 0
In the block <span>letter style, all components of the letter begin flush with the left margin.</span>
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Explain how the CPU processes data instructions.
Black_prince [1.1K]

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The actual mathematical operation for each instruction is performed by a combinational logic circuit within the CPU's processor known as the arithmetic logic unit or ALU.

Explanation:

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(e) The entries in each column of the array A are sorted into strictly increasing order.
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The answer is 3 because
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In 2-5 paragraphs, describe the points that Kendra needs to consider when choosing a telecommunications technology to meet her n
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For marketing requirements, various communication mediums like digital communication medium, as well as non digital traditional communication medium can be used. Some like Blogs, Article directories, forums etc. can be used.

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The above details covers all the requirements.

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3 years ago
Why is it grey? i recently dropped it , the switch is on!
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Express the following binary numbers in hexadecimal. (a) %100011100101 (b) %1011001111 (show work)
Lapatulllka [165]

Answer:

(100011100101)_{2} = (8E5)_{16} = %8E5

(1011001111) = (2CF)_{16} = %2CF

Explanation:

Binary and hexadecimal values have the following pair equivalences.

(0000)_{2} = (0)_{16}

(0001)_{2} = (1)_{16}

(0010)_{2} = (2)_{16}

(0011)_{2} = (3)_{16}

(0100)_{2} = (4)_{16}

(0101)_{2} = (5)_{16}

(0110)_{2} = (6)_{16}

(0111)_{2} = (7)_{16}

(1000)_{2} = (8)_{16}

(1001)_{2} = (9)_{16}

(1010)_{2} = (A)_{16}

(1011)_{2} = (B)_{16}

(1100)_{2} = (C)_{16}

(1101)_{2} = (D)_{16}

(1110)_{2} = (E)_{16}

(1111)_{2} = (F)_{16}

We convert from binary to hexadecimal selecting groups of 4 binary from the binary code, from the least significant bits(at the right) to the most significant bits(at the left). The conversion is an hexadecimal "string" from the last group you converted to the first. So:

(a) %100011100101

(0101)_{2} = (5)_{16}

(1110)_{2} = (E)_{16}

(1000)_{2} = (8)_{16}

So

(100011100101)_{2} = (8E5)_{16}

(b) %1011001111

(1111)_{2} = F_{16}

(1100)_{2} = C_{16}

(10)_{2} = (0010)_{2} = 2_{16}

(1011001111) = (2CF)_{16}

7 0
3 years ago
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