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3 years ago

If you have a room with four walls and a ceiling, how would you label the walls (plane, line, or point)? How would you label

Mathematics

1 answer:

Sergio039 [100]3 years ago

3 0

Walls = Plane

Intersection = line

Corner = Point

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A sample of 25 undergraduates reported the following dollar amounts of entertainment expenses last year:

Kaylis [27]

Answer:

mean = 724.2

Median = 715

Mode = 768

Range = 85

Standard deviation = 29.30

Interval = [665.6, 782.8]

Step-by-step explanation:

Number of samples n = 25

Summation X= 769 + 691 + 699 +730+711+ 765+ 702 718 +719 +712+ 768 +688 +757+695 768 +735 +709 +758 +708+ 693 +736 700+ 687 +772 +715 = 18105

1. Mean = 18105/25

= 724.2

2. Median is the middle value when arranged from the least value to the highest = 715

3. Mode is the number with the highest frequency = 768 (occured two times)

1. Range = highest value - lowest value

Highest value = 772

Lowest value = 687

772-687 = 85

2. Standard deviation = √(X-barX)²/n-1

= √20604/25-1

=√858.5

= 29.30

Please check attachment for the full calculation of the standard deviation

Interval

[Mean - 2(sd), mean + 2(sd)]

= [724.2-2x29.3, 724.2+2x29.3]

=[665.6, 782.8]

4 0

2 years ago

best answer will be awarded the brainliest and 5 stars choose the best estimate for 278 divided by 59 select the correct answer

Alex Ar [27]

278 divided by 59 is 4.712, which can be rounded to 5
the answer is d. 5

5 0

3 years ago

Read 2 more answers

Find the measure of the missing angles. Both of them is wrong. (Picture included)

Ymorist [56]

Answer: you need to add them together then add BAND D to the same expersion

6 0

3 years ago

Iron has a density of 7.9 g/cm³. Gold has a density of 19.3 g/cm³.

alexandr402 [8]

Density = m/v
3.86kg=3860g
d= 3860/200
= 19.3g/cm^3
therefore it is gold.

7 0

2 years ago

Simplify completely: 8x+4/x^3+23÷4x^2-10x-6/9-x^2

Helen [10]

Answer:

The simplified form is: $-x^2-2x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{2}{3}$

Step-by-step explanation:

To simplify the expression given we, need to open the brackets, and if there is power term. Then we need to group all the like terms and then arrange in the descending order of powers of the given expression.

Now the expression that is given to us is:

$8x+\frac{4}{x^3}+\frac{23}{4x^2}-10x-\frac{6}{9}-x^2$

Here we will simplify it by grouping the like terms, as follows:

$8x+\frac{4}{x^3}+\frac{23}{4x^2}-10x-\frac{6}{9}-x^2\\=-x^2+8x-10x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{6}{9}=-x^2-2x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{2}{3}$

So this is the required simplified form.

7 0

3 years ago