Answer:
C. CH4 + 202 – CO2 + 2H20
Explanation:
CH4+O2-CO2+H20
The above equation represents combustion of methane to produce carbon-dioxide and water.
One carbon atom is present on the reactant side as well as on the product side. Four hydrogen atoms are present on the reactant side and two hydrogen atoms on product side. In order to balance this equation, we would multiply water molecule by two. Now there are four atoms of oxygen in the product side but only two on reactant side, so we will multiply oxygen molecule by two on the reactant side. Now the equation is balanced.
The balanced chemical equation is:
CH4+202-CO2+2H2O
This equation obeys the law of conservation of mass as the mass of the reactants is same as that of the products.
Answer:
Explanation:
Hardy Weinberg equation is presented below and describes that in a population the frequency of alleles ad genotypes will remain static or the same in the absence of evolutionary disturbances such as mutation, migration ( gene flow), natural selection and with the population large and random mating
p² +2pq + q²
where p represents the frequency of the dominant alleles
q represent the frequency of the recessive alleles
p² represent the frequency of the dominant homozygous genotype
q² represent the frequency of the recessive homozygous genotype
2pq represent the frequency of the heterozygous genotype
q² also represent the frequency of the recessive phenotype
(p² + 2pq) represent the frequency of the dominant phenotype
Answer:
Plants require nitrogen to live, so plants in general depend on the nitrogen cycle and are a part of it. Explanation: Plants require nitrogen to live
Explanation:
Answer:
The offsprings of this punnet square will be Dd, Dd, dd and dd in a ratio 1Dd : 1dd
See attached image for punnet square completion
Explanation:
This question involves a cross involving a single gene with alleles D and d where allele D is dominant over allele d i.e. D will mask the phenotypic expression of d in a heterozygous state.
This cross is between a heterozygous parent (Dd) and a homozygous recessive parent (dd). Parent Dd will produce gametes D and d while parent dd will produce gametes d and d.
Using these gametes in a punnet square, four possible offsprings with two distinct genotypes will be produced. The genotypes are: Dd and dd in a ratio 1:1
Hence, the possibility of having a heterozygous dominant offspring is 1/2 while the possibility of having a homozygous recessive offspring is also 1/2.
Hes in the northern hemisphere and the south facing side is toward the equator
