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3 years ago

Need help with these two math questions

Mathematics

1 answer:

MaRussiya [10]3 years ago

8 0

√3 x √5 = √15

7√15 - 2√15 = answer 5√15

simple

6² = 36

7² = 49

8² = 64

√64

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How do i evaluate it????

Kitty [74]

Answer:

1 for all evaluate questions

Step-by-step explanation:

just remember anything to the zero power is 1

4 0

3 years ago

Rewrite each expression without a negative exponent none of the above<br>x^-1

Sloan [31]

Answer:

x^-1

x^1

Step-by-step explanation:

Oooops ...can you please repeat ur Question

3 0

3 years ago

Read 2 more answers

A trucking firm has a large inventory of spare parts that have been in storage for a long time. It knowsthat some proportion of

Debora [2.8K]

Answer:

$0.1546\leq \widehat{p}\leq 0.3513$

Step-by-step explanation:

The firm tests 75 parts, and finds that 0.25 of them are notusable

n = 75

x = 0.25 \times 75 = 18.75≈19

$\widehat{p}=\frac{x}{n}$

$\widehat{p}=\frac{19}{75}$

$\widehat{p}=0.253$

Confidence level = 95%

So, Z_\alpha at 95% = 1.96

Formula of confidence interval of one sample proportion:

$=\widehat{p}-Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}\leq \widehat{p}\leq \widehat{p}+Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}$

$=0.253-(1.96)\sqrt{\frac{0.253(1-0.253)}{75}}\leq \widehat{p}\leq0.253+(1.96)\sqrt{\frac{0.253(1-0.253}{75}}$

Confidence interval $=0.1546\leq \widehat{p}\leq 0.3513$

7 0

3 years ago

Please help me, i promise its worth it!!!

Rashid [163]

$\\ \sf\longmapsto 2(L+B)=55$

$\\ \sf\longmapsto 2(\dfrac{4}{3}x+x)=55$

$\\ \sf\longmapsto \dfrac{8}{3}x+2x=55$

$\\ \sf\longmapsto \dfrac{8x+6x}{3}=55$

$\\ \sf\longmapsto \dfrac{14x}{3}=55$

$\\ \sf\longmapsto 14x=165$

$\\ \sf\longmapsto x=11.78$

$\\ \sf\longmapsto x\approx 12$

Now

B=x=12
L=4/3(12)=4(4)=16

5 0

2 years ago

Read 2 more answers

A car is towed using a force of 1600N. The rope used to pull the car makes an angle of 25∘ with the horizontal. Find the work do

mezya [45]

Answer: 2900185 Joules

Step-by-step explanation:

Force used to tow the car is 1600N

Angle(α)= 25

Displacement = 2km

Recall that 1km= 1000m

Therefore 2km= 2000m

Workdone= FdCos α

W= 1600 * 2000 * cos 25

W=2900184.919

W= 2900185 Nm(when approximated to the nearest integer)

Since 1J = 1Nm

Work done = 2900185 J

5 0

3 years ago