Answer:
(-2,-12), (-1,-6), (0,-3) and (1,-3/2)
Step-by-step explanation:
g(x) = -3(1/2)^x
Putting values of x
x g(x)
-2 -3(1/2)^-2 = -12
-1 -3(1/2)^-1 = -6
0 -3(1/2)^0 = -3
1 -3(1/2)^1 = -3/2
Now, making the graph we will plot
(-2,-12), (-1,-6), (0,-3) and (1,-3/2)
The graph is shown in figure below.
Hello :
the line has same slope : y=3x 3 is the slope
<span> the point-slope form is :
y-(-12) = 3(x-2)
y+12 = 3(x-2)</span>
<span>The quadrilateral ABCD have vertices at points A(-6,4), B(-6,6), C(-2,6) and D(-4,4).
</span>
<span>Translating 10 units down you get points A''(-6,-6), B''(-6,-4), C''(-2,-4) and D''(-4,-6).
</span>
Translaitng <span>8 units to the right you get points A'(2,-6), B'(2,-4), C'(6,-4) and D'(4,-6) that are exactly vertices of quadrilateral A'B'C'D'.
</span><span>
</span><span>Answer: correct choice is B.
</span>
Answer:
36, 74,493
Step-by-step explanation:
