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2 years ago

15

Complete the table with values for x or y that make this equation true: 3x+y=15

1 answer:

Ipatiy [6.2K]2 years ago

7 0

Answer:

x=5

y=0

or

x=1

y=12

Step-by-step explanation:

I guess you can make it up as long as it equals 15, I guess that's what the question is saying??

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ASAP! Simplify -5 - square root -44

Tju [1.3M]

Answer:

$\boldmath-5-2i\sqrt{\boldmath11}$

Step-by-step explanation:

The not simplified form is $-5-\sqrt{-44}$

you know that $\sqrt{a\times b} = \sqrt{a} \times\sqrt{b}$ is true a and b are both positive or one of it is negative (not both of them).

You can write -44 as -1 × 4 × 11 inside square root.

So, $\sqrt{-44} = \sqrt{-1\times4\times11}=\sqrt{-1}\times\sqrt{4}\times\sqrt{11}=i\times2\times\sqrt{11}$ ( $\sqrt{4}=2$ )

$\therefore -5-\sqrt{-44} = -5-2i\sqrt{11}$

(NOTE : You must know that $\boldmath\sqrt{\boldmath-1}$ is written as $\boldsymbol i$ )

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3 years ago

Write an equation of a line that passes through the point (1, 2) and is perpendicular to the line y=-1/4x+2

Dmitriy789 [7]

Answer:

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3 years ago

Use the discriminant to find the number and type of solution for x^2+6x=-9

likoan [24]

Answer:

D = 0; one real root

Step-by-step explanation:

Discriminant Formula:

$\displaystyle \large{D = {b}^{2} - 4ac}$

First, arrange the expression or equation in ax^2+bx+c = 0.

$\displaystyle \large{ {x}^{2} + 6x = - 9}$

Add both sides by 9.

$\displaystyle \large{ {x}^{2} + 6x + 9 = - 9 + 9} \\ \displaystyle \large{ {x}^{2} + 6x + 9 = 0}$

Compare the coefficients so we can substitute in the formula.

$\displaystyle \large{a {x}^{2} + bx + c = {x}^{2} + 6x + 9 }$

a = 1
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Substitute a = 1, b = 6 and c = 9 in the formula.

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Since D = 0, the type of solution is one real root.

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