Answer:
y = 2(x-3)^2 -12
y = -4/9(x-2)^2 +7 bonus
Step-by-step explanation:
The vertex form of a parabola is
y = a(x-h)^2 + k where (h,k) is the vertex
y = a(x-3)^2 - 12
We have one point given (0,6)
6 = a (0-3) ^2 -12
6 = a (-3)^2 -12
6 = 9a-12
Add 12 to each side
6+12 = 9a
18 = 9a
Divide each side by 9
18/9 = 9a/9
a=2
y = 2(x-3)^2 -12
We follow the same steps for the bonus
y = a(x-2)^2 +7
Substitute the point into the equation
3 = a (-1-2)^2 +7
3 =a (-3)^2 +7
3 = 9a +7
subtract 7 from each side
3-7 = 9a +7-7
-4 = 9a
Divide by 9
-4/9 =a
y = -4/9(x-2)^2 +7
I’m not extremely good at math but I think you need to make -x-y=1 into y=mx+b form and then solve your new equation!
Answer:
f(x) = (x-2) (x+10)
Step-by-step explanation:
f(x)=x^2+8x-20
Factor the right hand side
What 2 numbers multiply to -20 and add to 8
-2 * 10 = -20
-2 + 10 = 8
f(x) = (x-2) (x+10)
Then we can use the zero product property to help us to find the zero's
Answer:
you just add the top numbers and then if its over the denominator you simplify
Step-by-step explanation:
7/9 + 4/9
10/9
1-1/9
Answer: Its C, 9.1
Step-by-step explanation: Did it on usa prept :)
