3 years ago

The expression (4 log a) - (1/2 log b) + log c is equivalent to:

Mathematics

1 answer:

Svetach [21]3 years ago

7 0

Answer:

log b

Step-by-step explanation:

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Step-by-step explanation:

$f(2)=\frac{m}{2-1}+n\\\\f(2)=\frac{m}{1}+n\\\\f(2)=m+n\\\\m+n=3\\m=3-n------(i)\\\\f(3)=\frac{m}{3-1}+n\\\\f(3)=\frac{m}{2}+n\\\\f(3)=\frac{m}{2}+\frac{n*2}{1*2}\\\\f(3)=\frac{m}{2}+\frac{2n}{2}\\\\f(3)=\frac{m+2n}{2}\\\\f(3)=2\\\\\frac{m+2n}{2}=2\\\\m+2n=2*2\\\\m+2n=4---------(ii)\\\\3-n+2n=4------{using(i)}\\\\3+n=4\\\\n=4-3\\\\n=1\\\\m=3-n=3-1\\\\m=2$

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