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Svetradugi [14.3K]

3 years ago

13

Ob's wife Bobette is looking for a new phone plan for their home because ever since the pandemic, all the kids have been using u

p their shared data! She's looking at two companies, Koodu and Fidu.
Koodu charges $50 a month plus $36 per 1 gigabyte of data over the limit. Fidu charges $35 a month plus $39 per 1 gigabyte of data over the limit.

At how many gigabytes over the limit, will the two companies charge the same amount of money?

1 answer:

Alex Ar [27]3 years ago

8 0

Answer:

5 gigabyte

Step-by-step explanation:

Let the GB data at which the charge for both company is same be x

For Kodu

monthly fixed charge = $50

Per GB data charge over limit = $36

charge for X GB data = Per GB data charge over limit *x = $36*x = 36x

Total charge for Kodu for x gb data = monthly fixed charge +charge for X GB data = $50 +$36

For Fidu

monthly fixed charge = $35

Per GB data charge over limit = $39

charge for X GB data = Per GB data charge over limit *x = $39*x = 39x

Total charge for Fidu for x gb data = monthly fixed charge +charge for X GB data = $35 +$39

Given that at at X GB data charge for both the company is same then

50 +36x = 35 +39x

39x - 36x = 50-35

=> 3x = 15

=> x = 15/3 = 5

Thus, at 5 GB over the limit, charge for both the company will be same.

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Step-by-step explanation:

Pick's theorem is a useful relationship in circumstances like these. It tells you the area is ...

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You can also get there by realizing the bounding rectangle is 4 units square. From that, corner triangles are cut. CW from upper left, those triangles have (base, height) dimensions of (3, 2), (1, 3), (3, 1), and (1, 2). So, the total of their areas is (1/2)(6 +3 + 3 +2) = 7 square units. The shaded area is then 16-7 = 9 square units, same as above.

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Step-by-step explanation:

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3 years ago

Maci and I are making a small kite. Two sides are 10". Two sides are 5". The shorter diagonal is 6". Round all your answers to t

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Answer:

A. 4".

B. Approximately 9.54".

C. Approximately 13.54".

Step-by-step explanation:

Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

We have been given that two sides of a kite are 10 inches and two sides are 5 inches. The shorter diagonal is 6 inches.

A. Since we know that the diagonals of a kite are perpendicular and one diagonal (the main diagonal) is the perpendicular bisector of the shorter diagonal.

We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

We can find the value of x using Pythagorean theorem as:

$(AO)^2=(AD)^2-(DO)^2$

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$x^{2}=25-9$

$x^{2}=16$

Upon taking square root of both sides of our equation we will get,

$x=\sqrt{16}$

$x=\pm 4$

Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

$(OC)^2=(DC)^2-(DO)^2$

Upon substituting our given values we will get,

$y^2=10^2-3^2$

$y^2=100-9$

$y^2=91$

Upon taking square root of both sides of our equation we will get,

$y=\sqrt{91}$

$y\pm 9.539392$

$y\pm\approx 9.54$

Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

$\text{The length of the longer diagonal}=x+y$

$\text{The length of the longer diagonal}=4+9.54$

$\text{The length of the longer diagonal}=13.54$

Therefore, the length of longer diagonal is approximately 13.54 inches.

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