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tester [92]
3 years ago
15

7b6+12b6 if canot be simplified

Mathematics
1 answer:
kramer3 years ago
6 0

Because b^6 is present in both terms, we can factor it out.

b^6(7 + 12)

Combine like terms.

b^6(19)

Rearrange.

19b^6 is the fully simplified form of the given expression.

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Find the domain and range of each relation. Then determine if the relation is a function. ​
Vlad [161]

Answer:

There is no fixed domain, meaning it is ongoing

The range is from -1 ≤ x ≤ 3

It is a function

Step-by-step explanation:

Domain refers to the x values. If there was a domain then there would be a dot or a point signalling that there is a fixed domain, however, there are arrows meaning that it will keep going.

The range refers to the y-values. The lowest y-value is -1 and the highest is 3.

It is a function because, when you do the vertical line test, each x-value has its own y-value.

3 0
3 years ago
Write a polynomial that is a trinomial, has the coefficients 3 and 4, the variable x,
vladimir1956 [14]

Answer:

3x+4x+7

Step-by-step explanation:

First, a Trinomial consists of three terms.

so we have <u>blank</u>+<u>blank</u>+<u>blank</u>

Next we need to add the coefficients.

<u>3</u>+<u>4</u>+<u>blank</u>

Add the variables.

3x+4x+<u>blank</u>

And lastly, add the constant.

3x+4x+7

Good luck!

8 0
3 years ago
Write 2 expressions that represent the areas of 4 triangles
arsen [322]
2-9x and 17x - 8x +2
4 0
3 years ago
Divide 12x 4 y 4 by 3x 2 y. A. 4x 6y 5 B. 4x 2y 3 C. 9x 6 D. 9x 2y 3
andrew-mc [135]

Answer:

\frac{12x^4y^4}{3x^2y}=4x^2y^3

Step-by-step explanation:

Consider an element a\neq 0

We know that \frac{a^m}{a^n}=a^{m-n}

Here, m and n are exponents and a is a base. Exponent refers to the no. of times a term is multiplied by itself. Another word for exponents is powers.

Other Properties of exponents:

a^m\times a^n=a^{m+n}\\a^0=1\\\left ( a^m \right )^n=a^{mn}

Here, we are required to divide 12x^4y^4 by 3x^2y.

Consider \frac{12x^4y^4}{3x^2y}

We will solve \frac{12}{3}\,,\,\frac{x^4}{x^2}\,,\,\frac{y^4}{y} separately.

Here,

\frac{12}{3}=4\\\frac{x^4}{x^2}=x^{4-2}=x^2\\\frac{y^4}{y}=y^3

So, \frac{12x^4y^4}{3x^2y}=4x^2y^3

8 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!
Alenkasestr [34]

Answer:

Tasha made her mistake in step 4.

7 0
3 years ago
Read 2 more answers
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