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2 years ago

9

Jon ate too many holiday cookies and gained 2.2 kilograms in December. Then he went on a diet and lost 1.5 kilograms in January.

Then lost another 3.7 kilograms in February. Jon wants to know the total change in his weight was over these three months. Which of the following equations matches the situation above

2 answers:

dezoksy [38]2 years ago

6 0

Answer:

2.2+(-1.5)+(-3.7)=?

Step-by-step explanation:

gogolik [260]2 years ago

5 0

Answer:

Jon lost a total of 3 kilograms in these 3 months.

Step-by-step explanation:

Weight that Jon gained in December = 2.2 kilograms

Weight that Jon lost in January = 1.5 kilograms

Weight that Jon lost in February = 3.7 kilograms

Overall Change in his weight = Total Weight he gained - Total weight he Lost

Total weight he gained is 2.2 kilograms as he only gained weight in December. Total weight he lost will be sum of weights he lost in January and February.

So, total weight Jon lost = 1.5 + 3.7 = 5.2 kilograms

Thus,

Total change in Jon's Weight = 2.2 - 5.2 = -3.0 kilograms

This shows that Jon lost a total of 3 kilograms in these 3 months.

Conclusion:

The statement that best describe the total change in his weight is: Jon lost a total of 3 kilograms in these 3 months

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5.01 *10^-7-30*10^-9

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Answer:

$\large\boxed{4.71\times10^{-7}}$

Step-by-step explanation:

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or

$5.01\times10^{-7}-30\times10^{-9}\\\\=5.01\times10^{-7}-30\times10^{-7+(-2)}\\\\=5.01\times10^{-7}-30\times10^{-7}\cdot10^{-2}\\\\=5.01\times10^{-7}-(30\cdot10^{-2})\times10^{-7}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=5.01\times10^{-7}-\left(30\cdot\dfrac{1}{10^2}\right)\times10^{-7}\\\\=5.01\times10^{-7}-\left(30\cdot\dfrac{1}{100}\right)\times10^{-7}\\\\=5.01\times10^{-7}-(30\cdot0.01)\times10^{-7}\\\\=5.01\times10^{-7}-0.3\times10^{-7}\qquad\text{distribute}\\\\=(5.01-0.3)\times10^{-7}\\\\=4.71\times10^{-7}$

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2 years ago

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Step-by-step explanation:

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