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erica [24]
2 years ago
9

Jon ate too many holiday cookies and gained 2.2 kilograms in December. Then he went on a diet and lost 1.5 kilograms in January.

Then lost another 3.7 kilograms in February. Jon wants to know the total change in his weight was over these three months. Which of the following equations matches the situation above
Mathematics
2 answers:
dezoksy [38]2 years ago
6 0

Answer:

2.2+(-1.5)+(-3.7)=?

Step-by-step explanation:

gogolik [260]2 years ago
5 0

Answer:

Jon lost a total of 3 kilograms in these 3 months.

Step-by-step explanation:

Weight that Jon gained in December = 2.2 kilograms

Weight that Jon lost in January = 1.5 kilograms

Weight that Jon lost in February = 3.7 kilograms

Overall Change in his weight = Total Weight he gained - Total weight he Lost

Total weight he gained is 2.2 kilograms as he only gained weight in December. Total weight he lost will be sum of weights he lost in January and February.

So, total weight Jon lost = 1.5 + 3.7 = 5.2 kilograms

Thus,

Total change in Jon's Weight = 2.2 - 5.2 = -3.0 kilograms

This shows that Jon lost a total of 3 kilograms in these 3 months.

Conclusion:

The statement that best describe the total change in his weight is: Jon lost a total of 3 kilograms in these 3 months

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Jan has $130. If she saves $25 per week, in how many weeks will she have $600?
serious [3.7K]

Let's represent the number of weeks with the variable 'w':

130 + 25w = 600

We subtract both sides by 130:

25w = 470

w = 18.8

We round up:

It will take her 19 weeks.

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Answer  

Find out the  length of OP .

To prove

As given

In △JKL, ​ JO=44 in. ​

Now as shown in the diagram.

JP , MK, NL be the median of the △JKL and intresection of the JP , MK, NL be O .

Thus O be the centroid of the  △JKL .

The centroid divides each median in a ratio of 2:1 .

Let us assume x be the scalar multiple of the OP and JO .

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JO = 44 in

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x = 22 in

Thus the length of the OP IS 22 in .







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elixir [45]

Answer:

A

Step-by-step explanation:

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Natasha2012 [34]
The answer is letter C
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3 years ago
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P (6,6) y=2/3x
matrenka [14]

Answer:

y = -\frac{3}{2}x+15

Step-by-step explanation:

Given:

Given point P(6, 6)

The equation of the line.

y = \frac{2}{3}x

We need to find the equation of the line perpendicular to the given line that contains P

Solution:

The equation of the line.

y = \frac{2}{3}x

Now, we compare the given equation by standard form y = mx +c

So, slope of the line m_{1} = \frac{2}{3}, and

y-intercept c=0

We know that the slope of the perpendicular line m_{1}\times m_{2}  = -1

m_{2}=-\frac{1}{m_{1}}

m_{2}=-\frac{1}{\frac{2}{3} }

m_{2}=-\frac{3}{2}

So, the slope of the perpendicular line m_{2}=-\frac{3}{2}

From the above statement, line passes through the point P(6, 6).

Using slope intercept formula to know y-intercept.

y=mx+c

Substitute point P(x_{1}, y_{1})=P(6, 6) and m = m_{2}=-\frac{3}{2}

6=-\frac{3}{2}\times 6 +c

6=-3\times 3 +c

c=6+9

c=15

So, the y-intercept of the perpendicular line c=15

Using point slope formula.

y=mx+c

Substitute m = m_{2}=-\frac{3}{2} and c=15 in above equation.

y = -\frac{3}{2}x+15

Therefore: the equation of the perpendicular line y = -\frac{3}{2}x+15

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