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Westkost [7]
3 years ago
7

A scale drawing has a scale of 0.25 in. : 12 ft. Find the length on the drawing for an actual length of 15 ft.

Mathematics
1 answer:
lesya [120]3 years ago
7 0

If 0.25 in on a drawing is 12 ft in real life, than 1 in on the drawing is 48 ft in real life.

Just divide 15 by 48

15/48=0.3125

So the length of 15 in real life to a drawing is 0.3125 inches.

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Is this even a question, it seems to be more of a statement..
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Snow is falling steadily in Syracuse, New York. After 2 hours, 4 inches of snow has fallen. Write an equation that gives the amo
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y=2x

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8 0
3 years ago
Please help me with the work because i dont understand this.
Alexandra [31]

Answer:

The dimension are 20 ft by 15 ft

Step-by-step explanation:

A = l*w

P = 2(l+w)

we know the area = 300

and the perimeter = 70

300 = lw

70 = 2 (l+w)

divide by 2

70/2 = 2/2 (l+w)

35 = l+w

subtract w

35-w = l+w-w

35 -w =l

substitute this into 300 = lw

300 = (35-w) * w

distribute

300 = 35w - w^2

subtract 300 from each side

0 = -w^2 +35w - 300

divide by -1

0 = w^2 - 35w + 300

factor

0= (w-15) (w-20)

using the zero product property

w-15 = 0   w-20 =0

so w=15, w=20

if w=15   then l=35 -w  l = 35-15   l=20

if w=20  then l=35-w   l= 35-20 = 15


The dimension are 20 ft by 15 ft

7 0
3 years ago
Subtract 5y2 -6y-11 from 6y2+2y+5
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Answer: y^2-4y-6

Step-by-step explanation:

5 0
2 years ago
What is the solution to the equation? 4√x-4 =3 <br><br> A. -8 B. 16 C. 85 D. no solution
kodGreya [7K]

{\qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

\qquad \sf  \dashrightarrow \:  \sqrt[4]{x - 4}  = 3

\qquad \sf  \dashrightarrow \: x - 4 = (3) {}^{4}

\qquad \sf  \dashrightarrow \: x - 4 = 81

\qquad \sf  \dashrightarrow \: x = 81 + 4

\qquad \sf  \dashrightarrow \: x = 85

So, the correct choice is 85

4 0
2 years ago
Read 2 more answers
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