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Black_prince [1.1K]
2 years ago
13

Sniffer turns the NIC of a system to the promiscuous mode so that it listens to all the data transmitted on its segment. It can

constantly read all information entering the computer through the NIC by decoding the information encapsulated in the data packet. Passive sniffing is one of the types of sniffing. Passive sniffing refers to:
Computers and Technology
1 answer:
Mamont248 [21]2 years ago
6 0

Answer:

The right answer will be "Sniffing through a hub".

Explanation:

  • Packet sniffer seems to be a device that listens for transmitted data on what seems like a channel. Sniffing enables the detection of data by individual people as it has been transferred throughout a cable.
  • Appropriate nodes are using this methodology to make a diagnosis of connection issues, or even just harmful programs to obtain confidential information, like authentication and encryption.
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What is the use of an NDP?
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It defines five ICMPv6 packet types for router solicitation,router advertisement,neighbor solicitation,neighbor advertisement,and network redirects.

Explanation:

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2. A host computer with an IP address of 172.16.29.155 using a subnet mask of 255.255.255.0 and a gateway of 172.16.29.1 pings a
ASHA 777 [7]

Answer:

From the host IP address and subnet mask, you can tell that both computers are on the same network. Host 172.16.29.155 will need to send an ARP request broadcast for 172.16.29.83 to get the MAC address and update its ARP table if the host 172.16.29.83 has not already done so.

Explanation:

<h2>ADDRESS RESOLUTION PROTOCOL (ARP)</h2>

Address Resolution Protocol (ARP) is a procedure for mapping a logical address known as the IP address to a physical address known as MAC (Media Access Control) address in a local area network. The job of the ARP is essentially to translate 32-bit addresses to 48-bit addresses and vice-versa when using IP Version 4 (IPv4) to communicate on the network.

Most of the computer programs/applications use logical address (IP address) to send/receive messages, however, the actual communication happens over the physical address (MAC address) this happens in the layer 2 of the OSI model. An ARP request is a broadcast, and an ARP response is a Unicast.

Scenarios when ARP is used:

Scenario-1: The sender is a host and wants to send a packet to another host on the same network.

·        Use ARP to find another host’s physical address

Scenario -2: The sender is a host and wants to send a packet to another host on another network.

·        Sender looks at its routing table.

·        Find the IP address of the next-hop (router) for this destination.

·        Use ARP to find the router’s physical address

Scenario -3: the sender is a router and received a datagram destined for a host on another network.

·        Router checks its routing table.

·        Find the IP address of the next router.

·        Use ARP to find the next router’s physical address.

Scenario -4: The sender is a router that has received a datagram destined for a host in the same network.

·        Use ARP to find this host’s physical address.

The situation in the question above falls under scenario-1. From the host IP address and subnet mask, you can tell that both computers are on the same network. Host 172.16.29.155 will need to send an ARP request broadcast for 172.16.29.83 so to get the MAC address and update its ARP table if the host 172.16.29.83 has not already done so.

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3 years ago
Write a program that reads a string consisting of a positive integer or a positive decimal number and converts the number to the
jeka94

Answer:

#include <iostream>

#include <string>

#include <stack>

#include <math.h>

using namespace std;

int main() {

  string s;

  double n=0;

  int position=0;  

  stack<int> wholeNumbers;

  cout<<"Enter a decimal number:";

  cin>>s;

  string::iterator counter = s.begin();

  while(*counter!='.' && counter!=s.end()){

      wholeNumbers.push(*counter-48);

      counter++;

      position=position+1;

     

  }

  for(int i=0;i<position;i++){

      n=n+(wholeNumbers.top()*pow(10,i));

      wholeNumbers.pop();

  }

  position=-1;

  if(counter!=s.end()){

      counter++;

  }

  while(counter!=s.end()){

      n=n+((*counter-48)*pow(10,position));

      position=position-1;

      counter++;      

  }

  cout<<n;

}

Explanation:

  • Inside the while loop, push the push a number to the wholeNumbers stack by subtracting it with 48.
  • Increment the counter and position variable by 1 inside the while loop.
  • Count the number of digit, push each digit to top of stack and find the end of the number,
  • Run a for loop up to the value of position variable and pop a value from the wholeNumbers stack.
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