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Alchen [17]
3 years ago
10

Convert to standard form: F(x) = 2x + 4

Mathematics
1 answer:
mote1985 [20]3 years ago
7 0
The answer will be F=2x/x + 4/x
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If
arlik [135]

Given:

In a right angle triangle θ is an acute angle and \tan\theta =\dfrac{3}{5}.

To find:

The value of \cos \theta.

Solution:

In a right angle triangle,

\tan \theta=\dfrac{Perpendicular}{Base}

We have,

\tan\theta =\dfrac{3}{5}

It means the ratio of perpendicular to base is 3:5. Let 3x be the perpendicular and 5x be the base.

By using Pythagoras theorem,

Hypotenuse=\sqrt{Perpendicular^2+base^2}

Hypotenuse=\sqrt{(3x)^2+(5x)^2}

Hypotenuse=\sqrt{9x^2+25x^2}

Hypotenuse=\sqrt{34x^2}

Hypotenuse=x\sqrt{34}

In a right angle triangle,

\cos \theta=\dfrac{Base}{Hypotenuse}

\cos \theta=\dfrac{5x}{x\sqrt{34}}

\cos \theta=\dfrac{5}{\sqrt{34}}

Therefore, the value of \cos \theta is \dfrac{5}{\sqrt{34}}.

8 0
3 years ago
7+a+8+a= pls help pls help
Alina [70]

Answer:

15+2a

Step-by-step explanation:

7+a+8+a=15+2a

7 0
3 years ago
Jack mails 10 packages that each weigh the same amount. If the combined weigh of all 10 package is 67 1/2 pounds, how much does
kykrilka [37]
The answer is 6.75, I hope this helped

7 0
3 years ago
Find the value of x and y that will make each quadrilateral a parallelogram.​
Tatiana [17]

Answer:

the opposite Angles sum up to give 180

Step-by-step explanation:

3y +3y = 180

y=30

if y = 30 the x = 55

are you clear?

7 0
3 years ago
Read 2 more answers
The specifications for an electronic device state that it is to be operated in a room with relative humidity ℎ defined by |ℎ − 5
Nadya [2.5K]

Answer: \Large\boxed{20 < h < 80}

Step-by-step explanation:

<u>Given inequality </u>

|h-50| < 30

<u>The goal of the question</u>

To find the minimum and maximum of the relative humidities

For this question, we need to solve the inequality

<u>Simplify the absolute value sign</u>

h-50 < 30          or          h-50 > -30

<u>Add 50 on both sides</u>

h-50+50 < 30+50          or          h-50+50 > -30+50

       \Large\boxed{h < 80}                   or                    \Large\boxed{h > 20}

Hope this helps!! :)

Please let me know if you have any questions

5 0
1 year ago
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