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dezoksy [38]
3 years ago
7

Find the volume of the sphere

Mathematics
1 answer:
irinina [24]3 years ago
3 0

Answer:

You have to use this formula v = ⁴⁄₃πr³ or another way would be by entering the value of the radius in google calculator.

Step-by-step explanation:

Hope this helped :)

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What is negative 32 equals six m minus two?
Ber [7]
The variable m should equal -5
6 0
3 years ago
Tyrese rolled his car 121.92 centimeters. How many INCHES did Tyrese roll his car? (Hint 1in= 2.54 cm
marissa [1.9K]

Answer:

48 Inches

Step-by-step explanation:

Since 1 inch is equal to 2.54 centimeters, then you divide 121.92 by 2.54 to get 48 inches or 4 feet.

5 0
3 years ago
A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the
Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{1}{455} = 0.0021

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{36}{455} = 0.0791

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0
3 years ago
Please really need help on this please
Vika [28.1K]
0,1 0,7 I think I use to do these
8 0
3 years ago
If θ is an acute angle and sin θ = 2 1 , then cos θ =
ss7ja [257]
First of all i think theres a mistakein the question;
i think it is sin θ = \frac{1}{2}

and then sin 30° = \frac{1}{2}

thus θ= 30°\frac{ \sqrt{3} }{2}
3 0
3 years ago
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