Answer:
1800
Step-by-step explanation:
The sum to n terms of an arithmetic sequence is
= 
[ 2a₁ + (n - 1)d ]
where a₁ is the first term and d the common difference
Here a₁ = - 27 and d = 6, thus
= 
[ (2 × - 27) + (29 × 6) ]
= 15( - 54 + 174)
= 15(120)
= 1800
Well when you round to the nearest 10 it will be 1 number after the point (this is due to that 10 only has one 0.) now we know that if there is a number bigger than 5 besides the number they ask you in this case the first after the point you will add 1 to that number. in this case you will add 1 to the 3. this will give you the answer of 56.4
Hope this helps
Answer: 1 & 4
Step-by-step explanation:
Just did it
The given above may be modeled by the arithmetic sequence with initial value (I) 2200 and common difference (d) of 70. The number of applicants every year can be written by the equation,
at = a1 + (n - 1) x d
From the given above, n is equal to 4. This corresponds to the term which is 3 years from now.
at = 2200 + (4 - 1) x 70 = 2410
Thus, the enrollment capacity would be 2410 students.
