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icang [17]
4 years ago
12

Which inequality shown in the graph

Mathematics
2 answers:
Dovator [93]4 years ago
8 0
<h2>Answer:</h2>

The inequality that is shown in the graph is:

                         y > -4

<h2>Step-by-step explanation:</h2>

From the graph that is provided to us we see that the graph is a dotted straight line ( This means that the inequality will be strict because we get a solid line when the inequality is a inequality with a equality sign) and the line is a horizontal line that passes through (0,-4) and the shaded region is towards the origin i.e. it passes the origin test.

Hence, the inequality is:

                  y > -4

valkas [14]4 years ago
4 0

Answer:

The answer is

y > -4

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A video store rents new movies for $5 and older movies for $4. The owner wants
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Answer:

2480 new movies

Step-by-step explanation:

1) First you need to find out how much money the 400 older movies made.

400*4=1600

2) Next subtract that amount from the amount of revenue that the wants.

14000-1600=12400

3) Divide the amount of leftover money by the amount that a new movie costs to rent

12400/5=2480

This means that in order to reach the desired amount of revenue the store must sell 2480 new movies.

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4 years ago
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A pilot wishes to fly from Bayfield to Kitchener, a distance of 100 km on a bearing of 105°. The speed of the plane in still air
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4 years ago
The safe load, L, of a wooden beam supported at both ends varies jointly as the width, w, the square of the depth,d, and inverse
vladimir1956 [14]

Answer:

Safe Load is 127 lb.

Step-by-step explanation:

Given:

Load (L) = 1090 lb.

width(w) = 6 in.

depth (d) = 9 in.

length (l) = 12 ft.

Since all other units are in inches and unit of length is in feet, So we will convert foot into inches we get;

1 feet = 12 inches

12 feet = 12\times12 =144 in.

Hence length(l)= 144 in.

Now also Given

Load varies directly with width and square of depth and inversely with length.

Hence we can say that;

L∝ \frac{wd^2}{l}

Hence L=\frac{kwd^2}{l} where k is constant.

Now Substituting the given values we will find the value of k we get;

1090=\frac{k\times6\times9^2}{144}\\\\1090=\frac{k\times6\times81}{144}\\\\1090\times144= 486k\\\\k=\frac{1090\times144}{486}\approx 322.96

Also Given:

width(w) = 5 in.

depth(d) = 4 in.

length(l) = 17 ft.

1 ft. = 12 in.

17 ft = 12 \times 17 = 204\ in.

Hence length(l) = 204 in.

k = 322.96

We need to find the load beam(L);

L=\frac{kwd^2}{l}

Substituting new values we get;

L = \frac{322.96\times 5\times 4^2}{204} = \frac{322.96\times 5\times 16}{204} = 126.65\ lb

Rounding the load in nearest pound we get;

Load beam(L) = 127 lb

Hence Safe  Load is 127 lb.

3 0
3 years ago
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