3 years ago

How do you solve this equation 3^3x-7=81^12-3x

1 answer:

6 0

I think you meant...

3^(3x-7)=81^(12-3x) (note that 81=3^4) so

3^(3x-7)=3^4^(12-3x)

3^(3x-7)=3^(48-12x) taking log or natural log of both sides show that

3x-7=48-12x

15x=55

x=11/3

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