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lozanna [386]
3 years ago
13

How do you solve this equation 3^3x-7=81^12-3x

Mathematics
1 answer:
slavikrds [6]3 years ago
6 0
I think you meant...

3^(3x-7)=81^(12-3x)    (note that 81=3^4) so

3^(3x-7)=3^4^(12-3x)

3^(3x-7)=3^(48-12x)  taking log or natural log of both sides show that

3x-7=48-12x

15x=55

x=11/3
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elena-14-01-66 [18.8K]

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(3x) \times 3 - 2 = 1

(3x \times 3) - 2 = 1

9x - 2 = 1

Add sides 2

9x - 2 + 2 = 1 + 2

Simplification

9x = 3

Divide sides by 9

\frac{9x}{9}  =  \frac{3}{9}  \\

\frac{9}{9} x =  \frac{3}{9}  \\

x =  \frac{3}{3 \times 3}  \\

x =  \frac{1}{3}  \\

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4 0
3 years ago
HELP ONLY ANSWER QUESTION 10. THANKS
swat32
X - 5 = x^2

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4 years ago
Solve. −815x=2.24 Enter your answer as a mixed number in simplest form in the box. x =
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x=2.7 x 10*-3

Step-by-step explanation:

-815x=2.24

x=-2.24/815

x=2.7 x 10*-3

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Help me will give brain
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Answer:

The answer is C

Step-by-step explanation:

Let's solve your equation step-by-step.

4(x−2)=6x+18

Step 1: Simplify both sides of the equation.

4(x−2)=6x+18

(4)(x)+(4)(−2)=6x+18(Distribute)

4x+−8=6x+18

4x−8=6x+18

Step 2: Subtract 6x from both sides.

4x−8−6x=6x+18−6x

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Step 3: Add 8 to both sides.

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Step 4: Divide both sides by -2.

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Answer:

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3 years ago
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